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# Biomechanics

### Acceleration

Question | Answer |
---|---|

Acceleration | rate of change of velocity |

Acceleration equation | Vfinal - Vinital / ΔT = ΔV / ΔT |

increasing velocity - positive acceleration | positive direction |

decreasing velocity - negative acceleration | positive direction |

increasing velocity - negative acceleration | negative direction |

decreasing velocity - positive acceleration | negative direction |

Positive net force = | positive acceleration |

At peak of the a jump, V=0. when V=0 and CG = 0. What is your acceleration? | Negative acceleration because you have body weight. |

Negative net force = | negative acceleration |

Force | the push or Pull on the body measured in Newtons (N) |

Law #1 | Law of inertia |

Law #2 | Law of acceleration |

Law #3 | Law of action/reaction |

Law of inertia | a body will continue in its state of rest or motion unless a net force acts on it |

Law of acceleration | if net force acting on a body is not zero, the body will experience acceleration proportional to the force applied ( ∑F = m X a ) |

Law of action/reaction | for every action, there is an equal & opposite reaction |

if GRFv = W | ∑F = 0 ( no net force) & Acg =0 |

if GRF v > W | ∑F > 0 (net force upwards) & Acg > 0 (positive) |

if GRFv < W | ∑F < 0 (net force downward) & Acg < 0 (negative) |

∑F = 0 & Acg =0 | -CG motionless (stationary) -CG moving with a constant velocity |

∑F = 0 > & Acg =0 | -speed of CG is INCREASING as it moves UPWARDS (+ direction) -speed of CG is DECREASING as it moves DOWNWARD (-direction) |

∑F = 0 < & Acg =0 | -speed of CG is DECREASING as it moves UPWARDS (+ direction) -speed of CG is INCREASING as it moves DOWNWARDS (- direction) |

Created by:
rmart11