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Biomechanics
Acceleration
| Question | Answer |
|---|---|
| Acceleration | rate of change of velocity |
| Acceleration equation | Vfinal - Vinital / ΔT = ΔV / ΔT |
| increasing velocity - positive acceleration | positive direction |
| decreasing velocity - negative acceleration | positive direction |
| increasing velocity - negative acceleration | negative direction |
| decreasing velocity - positive acceleration | negative direction |
| Positive net force = | positive acceleration |
| At peak of the a jump, V=0. when V=0 and CG = 0. What is your acceleration? | Negative acceleration because you have body weight. |
| Negative net force = | negative acceleration |
| Force | the push or Pull on the body measured in Newtons (N) |
| Law #1 | Law of inertia |
| Law #2 | Law of acceleration |
| Law #3 | Law of action/reaction |
| Law of inertia | a body will continue in its state of rest or motion unless a net force acts on it |
| Law of acceleration | if net force acting on a body is not zero, the body will experience acceleration proportional to the force applied ( ∑F = m X a ) |
| Law of action/reaction | for every action, there is an equal & opposite reaction |
| if GRFv = W | ∑F = 0 ( no net force) & Acg =0 |
| if GRF v > W | ∑F > 0 (net force upwards) & Acg > 0 (positive) |
| if GRFv < W | ∑F < 0 (net force downward) & Acg < 0 (negative) |
| ∑F = 0 & Acg =0 | -CG motionless (stationary) -CG moving with a constant velocity |
| ∑F = 0 > & Acg =0 | -speed of CG is INCREASING as it moves UPWARDS (+ direction) -speed of CG is DECREASING as it moves DOWNWARD (-direction) |
| ∑F = 0 < & Acg =0 | -speed of CG is DECREASING as it moves UPWARDS (+ direction) -speed of CG is INCREASING as it moves DOWNWARDS (- direction) |