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gen chem
redox
Question | Answer |
---|---|
_____ loss of electron | oxidation |
OIL RIG | oxidation is loss electrons Reduction is gain electrons |
oxidation of free atoms like H2 | 0 |
oxidation of monoatomic ion NA+ | = charge of ion |
oxidation of Grp 1 and grp 2 elements | +1 and +2 |
oxidation of grp VII | -1 |
oxidation of H | -1 with less electroneg elements +1 with more electroneg elements |
oxidation of O | -2 +2 with more electroneg elements -1 in peroxides (o-o) or BaO2 |
balancing redox rxns | in acidic soln we add H2O i basic soln we add OH |
for electrodes AN OX RED CAT | anode - oxidation Reduction at cathode |
galvanic cells/ Daniel cell/battery have _______ rxn | spontaneous - forms electric energy -G |
electrolytic cells have ________ rxn | nonspontaneous - uses electrical energy |
flw of electrons in daniel cell | anode (abundance of electrons cuz its where oxidation occurs) to cathode |
in electrolytic cells the anode | positive |
in electrolytic cell the cathode | negative |
in galvanic cell the anode | negative |
in galvanic cell the cathode | positive |
reduction potential E* | tendency to become reduced |
more positive E_______ | greater tendency to be reduced |
Tl+ + e- ----> Tl(s) E= -.34 | oxidized therefore Tl(s) oxidized to Tl+ E=+.34 |
standard emf of galvanic cell is | positive |
standard emf of electrolytic cell is | negative |
gen formula emf | E red + E oxid |
G is negative when emf is | positive |
more negative E | greater tebdency to be oxidzed |
Sm3+ + Rh +6Cl- ----> [RhCl6]^3- + Sm Sm3+= -2.41 [RhCl6]^3= +.044 wats the EMF?? | determine oxidation and reduction of half rxn the more positive would be reduced the more negative would be oxidized for the oxidized reverse the sign to positive and flip the eqn then add the emfs =-2.85 |
if the redox and the emf have different results | the E is going to be negative and an electrolytic cell therefore nonspontaneous |