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EK Physics 1
Translational motion
| Question | Answer |
|---|---|
| for constant acceleration, distance = | x = x0 + v0*t + 1/2*a*t^2 |
| for constant acceleration, velocity = | v = v0 + a*t |
| for constant acceleration, velocity^2 = | v^2 = v0^2 + 2*a*x |
| average velocity = | vavg = 1/2*(v+v0) |
| x vs. t graph | slope = instantaneous velocity straight line = constant velocity curved line = changing velocity (acceleration) |
| v vs. t graph | slope = instantaneous acceleration straight line = constant acceleration curved line = changing acceleration area beneath the curve = total displacement |
| projectile motion | body projected by external force and continuing in motion by its own inertia |
| peak height of projectile found by.. | v0*sin(theta) = sqrt(2*g*h) |
| what dictates time of flight for projectile? | vertical velocity only |
| air resistance | created when projectile collides with air molecules; increased with large surface area, smooth surfaces experience less, generally higher v means higher air resistance |
Created by:
miniangel918
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