Save
Busy. Please wait.
Log in with Clever
or

show password
Forgot Password?

Don't have an account?  Sign up 
Sign up using Clever
or

Username is available taken
show password


Make sure to remember your password. If you forget it there is no way for StudyStack to send you a reset link. You would need to create a new account.
Your email address is only used to allow you to reset your password. See our Privacy Policy and Terms of Service.


Already a StudyStack user? Log In

Reset Password
Enter the associated with your account, and we'll email you a link to reset your password.
focusNode
Didn't know it?
click below
 
Knew it?
click below
Don't Know
Remaining cards (0)
Know
0:00
Embed Code - If you would like this activity on your web page, copy the script below and paste it into your web page.

  Normal Size     Small Size show me how

chadchem2

chem notes 2

QuestionAnswer
Amphoteric can act as an acid or a base; H2O
If we want the conjugate Base, then H2O acting as an acid (proton donor); H20--> H+ + OH- (CB)
If we want the conjugate Acid, then H2O is acting as a base( proton acceptor) H20--> H3O+ (CA)
Strong ACIDS::: 7 of them HCl; HBr; HI; H2SO4; HNO3; HCLO4; HCLO3
Strong BASES:: 8 of them LiOH; NAOH; KOH; RbOH; CsOH; ---> Group 1 & then Ca(OH)2; Sr(OH)2; Ba(OH)2 ----> Group 2
Ba(OH)2 Barium Hydroxide
Oxyacidic Trend: More OXYGEN= more Acidic for Oxyacid i.e. HCLO<HCLO2
Oxyacidic Trend: More ELECTRONEGATIVE the element= more Acidic ( stronger) ....NOT including H or O......I.e. HCLO3 > HBrO3
More acidic more stable; larger; weaker conjugate base
Kw of water= 1X 10 ^-14
Kw= [H+] [OH-]
Ka*Kb= Kw
pH= -log[H+]
pOH= -log[OH-]
[H+]*[OH-]= 1X 10^-14
pH+ pOH= 14
H+= 10^-pH
OH- = 10^-pH
As -OH goes up (inc)....pOH goes ______? DOWN (Dec)
1M HCL will have a pH of ?? 0
10 M HCL will have a pH of ??? and a pOH of ?? pH= -1 and pOh= 15
weak acid _____ dissociated; Strong acid _____ dissociates weak acid= partially dissociates; strong acids= fully dissociates
Shortcut to find weak acid pH:: when Ka is given [H3O+] = sqrt Ka*HA
Shortcut to find weak base pOH:: when Kb is given [OH-] = sqrt Kb*A-
Moles and pH are ______ proportional inversely
Dissociation of a weak base A- + H20= OH- + HA
Dissociation of a weak acid HA+ H20= H30 + A-
HF + CL- ---> HCL + F- HF= weak acid; CL- = weak conjugate base; HCL= strong acid; F- = strong conjugate base
Equilibrium favors the ______ side in a dissociation rxn ??? weaker side (side with weaker acid/ or base)
INCREASE Ka= _____ pKa? DECREASE ----> stronger acid
INCREASE Kb= ______ pKb? DECREASE ----> stronger base
Cations (+)- neutral salt...8 conjugate acids conjugate acid of strong bases....Li+, K+, Na+, Rb+, Cs+, Ca 2+, Sr 2+, Ba 2+
Anion (-) - neutral salt......7 conjugate bases conjugate base of strong acid.....Cl-, Br-, I-, NO3-, CLO4-, CLO3-, HSO4-
Anions usually BASES w/ exception to the 7 conjugate bases of the strong acids
Cations usually ACIDS w/ exception to the 8 neutral conjugate acids of the strong bases
More positively charged= the better the _____ acid ( cation)
To find out if a salt is acid or base...i.e. CsF Cs is a neutral cation ( so its crossed out), and the F has a charge of -1 on table...so its basic ( anion)
NaNO3 ( Sodium Nitrate) has a pH of?? pH= close to 7 because both Na and NO3- are neutral species.
Resists change in pH buffer
Buffer is a combination of.... weak acid and its conjugate base.......OR.......weak base and its conjugate acid; BOTH needed in equal amounts
Buffer can be _____ or ____ away from pH value... +1, -1
Acid/ base pH is scaled based on powers of _____ 10; i.e. pH of 2 is 1000 more acidic than pH of 5
For a Buffer pH equation use :: Henderson Hasselbach ::: pH= pKa+ log (A-)/ (HA)
10x more acid than base = drop one unit from pKa value
100x more acid than base = drop 2 unit from pKa value
10x more base than acid= RAISE 1 unit from pKa value
100x more base than acid= RAISE 2 unit from pKa value
First Law of Thermodynamics Energy can NOT be created nor destroyed
Second Law of Thermodynamics For a spontaneous process, ΔS universe> 0; ΔS system + Δ S surroundings > 0
Third Law of Thermodynamics A perfect crystal at 0 K has ZERO entropy
Change in work energy ΔE= q + w ; q= change in heat energy & w= change in work energy
System looses heat if q= negative (-)
System absorbes heat if q= positive (+)
System does work if w= negative (-)
System has work done on it if w= positive (+)
Gas expands then w= negative (-)
Gas compressed then w= positive (+)
w= - PΔV
locked piston = constant volume
As heat (Temp) increases, then ... Pressure increase (P and T are directly related)
Cool= expanding gas
Heat compressing gas
Isobaric constant pressure; ΔP= 0
Isochoric ΔV=0 & w= 0...think v0w isochoric
Isothermal constant temp; ΔT= 0, then ΔE=0
Adiabatic NO heat allowed in or out; q=0
Altitude Change= State function= doesnt matter the path taken ( independent) just matters start and finish
Everything are State Functions EXCEPT: 2 of them q and w ; Even though ΔE= state fx
Path Dependent q and w
Solids have the _____ Entropy ( disorder) ΔS Least amount out of a s,l,g
Gasses have the ____ Entropy ( disorder) ΔS MOST amount
S--> L---> G ΔS=? postitive
G--->L---->S ΔS=? negavite
More moles of gas= ____ entropy more
in a rxn if we go left to right according to the number of moles of gas ( more moles of gas on right then left) Δ S= positive
If products + reactants have the same # of moles of gas ...then Entropy= close to 0 or very small
Enthalpy ΔH= q x p
ΔH<0 Exothermic ( release heat)
ΔH>0 Endothermic ( absorb heat)
if the soln is cold .... endothermic rxn occuring
if the soln if warm.... exothermic rxn occuring
Bond Enthalpy (D) Amnt of energy needed to break a bond
break bond= ENDO ( energy needed in system)
Make bond= EXO ( release energy in a system)
ΔH= bonds broken- bonds formed
Enthalpies of formation ΔHf= products- reactants
ΔHf for any element in it's standard state = 0 ... i.e. Cl2
ΔHf= forms exactly ____ moles of any product & forms elements in their standard state 1 M
Hess's law: Change in ΔH is same regardless of path taken
Gibb's free energy (ΔG) Energy that is free to do work
ΔG<0 Spontaneous
ΔG>0 non- spontaneous
ΔG= 0 equilibrium
ΔG= products- reactants
ΔG= ΔH-TΔS ; Get High Test Scores
Room temp = 25 degrees C standard conditions
ΔH= - .......ΔS= + Spontaneous for all temp
ΔH= + .......ΔS= - Non spontaneous for all temp
ΔH= - .......ΔS= - Spontaneous at low temp
ΔH= + .......ΔS= + Spontaneous at High temp
Oxidation State Rules...Get their typical oxidation states #1 Group 1 or 2 Metals ; #2 H+ is +1 except when bonded to a metal; #3 More electronegative elements get their typical oxidation states
Permangenate MnO4-
Iodide I-
SOdium Azide NaN3
In Redox Reactions... if #e- is on the product side oxidation
In Redox Reactions... if #e- is on the reactant side reduction ( think reactant reduction RR)
In finding E for the reduction potential rxns... dont worry about coefficients, just change sign if reverse is needed
The standard electrode reduction potential E for H= 0v
shift right= E cell Increases= spontaneous
shift left= E cell dencreasses= non spontaneous
E cell= cell potential or EMF
for E cell shifting... only ____ matter not s or L aq
add more reactant, shift to the left
add more product , shift to the right
add more solid or Liquid, shift to the NO shift because s and L are not counted
Increase pH ( loosing H+ and becomes more basic) , shift to the the side with more H+ ions
Decrease pH ( adding H+ and becomes more acidic), shift to the the side with less H+ ions
Nerst :: E= E - [.0592/ n] log Q ; where n= number of moles transfered in rxn; and Q= products/ reactant
strongest oxidizing agent= gets reduced most positive v
strongest reducing agent = gets oxidized most negative v ( think RAN....reducing agent negative)
In a redox rxn if sum = NEGATIVE ...then rxn is not spontaneous
In a redox rxn if sum = POSITIVE ...then rxn is spontaneous
For Spontaneous rxns;; ΔG=___; Ecell = ____; Q___K negative; positive; Q<K If one is true then all is true
Electrolysis= Destruction of electricity; consumes electricity; have to have moving ions;
molten electrolysis= melt salt
NaBr (liguid)= molten b/c its a liquid
Grams made by electrolysis:: (AMPS) ( t in seconds) ( mw) / ( n) ( Faraday= 96,000)
Reductant= gets oxidized
Oxidant= gets reduced
Galvanic/ Voltaic Cells Spontaneous
Cell potential/ EMF= E>0; ΔG<0 Galvanic/ Voltaic Cells
Produces electricity Galvanic/ Voltaic Cells
RED CAT & AN OX Galvanic/ Voltaic Cells
e- go from ANODE ---> CATHODE Galvanic/ Voltaic Cells
ions float in and out of bridge; keep solns neutral; necessary for battery; SALT bridge
In a salt bridge....anions go to _____ & cations go to _____ anode; cathode
NON- spontaneous/ consumes energy ELectrolytic cell
E<0 ; ΔG>0 for _____ cells Electrolytic cell
In a electrolytic cell, anode is ____ & cathode is ____ +; -
In a electrolytic cell electrons move from ANODE (-)----> Cathode (+)
Created by: zrsoori
Popular DAT sets

 

 



Voices

Use these flashcards to help memorize information. Look at the large card and try to recall what is on the other side. Then click the card to flip it. If you knew the answer, click the green Know box. Otherwise, click the red Don't know box.

When you've placed seven or more cards in the Don't know box, click "retry" to try those cards again.

If you've accidentally put the card in the wrong box, just click on the card to take it out of the box.

You can also use your keyboard to move the cards as follows:

If you are logged in to your account, this website will remember which cards you know and don't know so that they are in the same box the next time you log in.

When you need a break, try one of the other activities listed below the flashcards like Matching, Snowman, or Hungry Bug. Although it may feel like you're playing a game, your brain is still making more connections with the information to help you out.

To see how well you know the information, try the Quiz or Test activity.

Pass complete!
"Know" box contains:
Time elapsed:
Retries:
restart all cards