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MP - Lecture 26
Pulmonary Gas Exchange and O2 Transport
| Question | Answer |
|---|---|
| Medical Physiology – Lecture 26 | Pulmonary Gas Exchange and O2 Transport |
| Diffusion of O2 from air to blood consists of two reversible processes: | O2 diffusion from air to RBC interior and dissolved O2 binding to Hb |
| Both processes of O2 diffusion rapidly reach: | Equilibrium |
| At equilibrium, PO2 = | PO2 in air |
| At equilibrium, dissolved O2 and HbO2 depends on: | PO2 |
| P50 represents: | Pressure at which Hb is 50% saturated |
| P50 increase means O2 affinity: | Decreased (right-shift) |
| P50 can be increased by: | High temperatures, 2,3-DPG, high CO2, and low pH |
| Pulse oximeter measures: | Absorbance ratio at two different wavelengths (HbO2 and Hb) to determine saturation |
| Pulse oximter does not measure: | Arterial O2 content |
| O2 content depends on: | Hb saturation and amount |
| Hb saturation depends on: | PO2 and dissociation curve |
| O2 content (mL O2 / 100 mL blood) = | (1.34) x (Hb saturation) x (Hb content) |
| O2 content if 100% saturation and 15g/100 mL blood = | (1.34) x (1.0) x (15) = 20 |
| O2 content if PO2 = 26 mmHg and 15g/100 mL blood = | (1.34) x (0.5) x (15) = 10 |
| Amount of O2 dissolved in blood at PO2 = 100 is: | 0.3, minor contribution |
| Amount of dissolved O2 in blood at PO2 = 1000 is: | 3, significant contribution |
| Rate of diffusion between air and blood is proportional to: | Surface area |
| Rate of diffusion between air and blood is inversely proportional to: | Thickness of barrier |
| PO2 at the pulmonary capillary end equals: | PAO2 |
| CO2 partial pressure difference is smaller compared to O2, but same amount of diffusion because: | CO2 has higher solubility |
| Inspired air PO2 | 150 mmHg |
| Inspired air PCO2 | ~0 mmHg |
| Alveolar air PO2 | 100 mmHg |
| Alveolar air PCO2 | 40 mmHg |
| Why don’t alveolar PO2 and PCO2 not change with each breath? | They do but very subtle changes |
| Steady state and gas composition is determined by: | Alveolar ventilation |
| VCO2 = | (VA) x (PACO2/760) |
| Hyperventilation increases O2 content by: | Small increase |
| Hypoventilation causes: | PACO2 increase, PO2 decrease |
| Alveolar PO2 and PCO2 change in ___ direction with ___ magnitudes. | Opposite, similar |
| If O2 content and VA change by the same factor, PAO2 and PACO2: | Do not change |
| Alveolar Gas Equation | PAO2 = PIO2 – (PACO2/R), where R = 0.8 in balanced diet |
| During hypoventilation, supplemental O2: | Corrects hypoxemia, but not hypercapnia |