Question 1

List

Accepted Answer

Ordered, Resizable, Mutable, Allows duplicates. myList = [1, 2]

Question 2

Setting list elements

Accepted Answer

If the element exists in the list, it can be set using the assignment operator. Using an element in a list is just like using a variable

Question 3

in / not in operator

Accepted Answer

Takes an element and a list and returns True if the element can be found in the list and False otherwise. Not in performs the opposite. 30 in numList

Question 4

Iterating through a list using a for loop

Accepted Answer

for selectedFruit in fruit: print(selectedFruit)

Question 5

Iterating through a list using a for loop and length

Accepted Answer

for i in range(len(fruit)): selectedFruit = fruit[i]  |  print(selectedFruit)

Question 6

+

Accepted Answer

Concatenate two lists. [1, 2] + [3, 4] gives you [1, 2, 3, 4]

Question 7

*

Accepted Answer

Repeats the elements of a list for a given number of times. [1, 2, 3]*3 gives you [1, 2, 3, 1, 2, 3, 1, 2, 3]

Question 8

[]

Accepted Answer

Used to extract an element that is positioned at a given index in the given list (ex. list[index]). Positive indexes start from the front with 0 being the first index. Negative indexes start from the back with -1 being the last index

Question 9

[:]

Accepted Answer

Allows the extraction of entire section of elements. [lower-bound: upper-bound]. Lower is inclusive, Upper is exclusive. Both bounds are optional. list[1:3] returns [b, c]. list[:2] returns [a, b]

Question 10

[::]

Accepted Answer

Slicing with a specified step (skip value). [lower-bound : upper-bound : step]. Step is the number of elements to be skipped plus 1. Can be negative, meaning case elements are extracted in reverse order. [1: 9: 2] gives you [20, 40, 60, 80]

Question 11

append()

Accepted Answer

Adds to the end of a list. name.append("Fred")

Question 12

index()

Accepted Answer

Returns the first index where that value is. name.index("Jill")

Question 13

extend()

Accepted Answer

Appends a list. name.extend(["Bob, "Jill"])

Question 14

insert()

Accepted Answer

Inserts at specified index. name.insert(0, "Mike")

Question 15

pop()

Accepted Answer

Remove element at index. name.pop(1)

Question 16

remove()

Accepted Answer

Removes first occurrence. name.remove("Bob")

Question 17

sort()

Accepted Answer

Sorts list alphanumerically. name.sort()

Question 18

Set

Accepted Answer

Unordered, No index, Fixed, no Duplicates, Resizable. fruit = {"apple", "banana"}

Question 19

update(<collection>)

Accepted Answer

Adds a collection to the set

Question 20

Joining sets using union

Accepted Answer

purchased = fruit1.union(fruit2)

Question 21

Joining sets using update

Accepted Answer

fruit1.update(fruit2)

Question 22

Intersecting sets

Accepted Answer

Get set of elements in first set that are also in second set. inBoth = fruit1.intersection(fruit2)

Question 23

Updating a set with its intersection

Accepted Answer

fruit1.intersection_update(fruit2)

Question 24

Difference in sets

Accepted Answer

Get set of elements from first that that is not in second set. unique = fruit1.difference(fruit2)

Question 25

Updating a set with its differences

Accepted Answer

fruit1.difference_update(fruit2)

Question 26

Tuple

Accepted Answer

Ordered, Fixed, allows Duplicates, not resizable. fruit = ("apple", "banana")

Question 27

Updating a tuple

Accepted Answer

Convert it to a list, modify it, then convert it back to a tuple

Question 28

Unpacking a tuple

Accepted Answer

Assigns each element to a corresponding variable. For example, a, b, c = ("apple", "banana", "cherry") assigns "apple" to a, "banana" to b, and "cherry" to c

Question 29

index()

Accepted Answer

Returns the first index where that value is. name.index("Jill")

Question 30

count()

Accepted Answer

Counts number of occurrences in the list. name.count("Mike")

Question 31

Dictionaries

Accepted Answer

Ordered, Resizable. Elements(called items) are made of a key and a value. Fixed key and mutable values. Keys are unique, values can be duplicates. person = { "person1" : "Bob", "person2" : "Jill"}

Question 32

Accessing dictionary items

Accepted Answer

Use key to access item's value. person[] or person.get()

Question 33

Get list of keys

Accepted Answer

person.keys()

Question 34

Get list of values

Accepted Answer

person.values()

Question 35

Change or add dictionary items

Accepted Answer

person[] = OR person.update({ : })

Question 36

Dictionary for loops

Accepted Answer

for value in person: print(value)

Question 37

update({: })

Accepted Answer

Add or update an item

Question 38

pop(<key>)

Accepted Answer

Remove element at index. name.pop(1)

Question 39

items()

Accepted Answer

Returns a list of key values as tuples

Question 40

Strings

Accepted Answer

Ordered, Indexed, Fixed, Not resizable

Question 41

split([separator])

Accepted Answer

Split string into list with separator

Question 42

Characters

Accepted Answer

Strings with one element (no dedicated type). Encoded using ASCII or Unicode

Question 43

strip()

Accepted Answer

Removes space from start and end

Question 44

split(<separator>)

Accepted Answer

Split string into tuple on first occurrence of separator

Question 45

splitlines()

Accepted Answer

Split string into list with new lines

Question 46

replace(, )

Accepted Answer

Replaces all occurrences of the substring with in a string

Question 47

partition(<separator>)

Accepted Answer

Split string into tuple on first occurrence of separator

Programming #4

From all lessons in "Organizing Data"

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