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BSC2011L
Natural Selection Color Variation Over Time in Rock Pocket Mouse Populations
| Question | Answer |
|---|---|
| Which of the following apply to the development of streptomycin resistance in E. coli? | The E. coli population has genetic variation. The selective agent is streptomycin. The mutation resulting in streptomycin resistance is random. |
| How will you select and grow a resistant strain of E. coli in this experiment? | Expose a sample of E. coli to streptomycin by inoculating it onto a streptomycin positive plate. Any colonies that grow will carry a mutation for resistance. |
| Let's say you inoculate four agar plates, each containing a different antibiotic (A, B, C, and D), and you add a swab from a lesion taken from a patient. After incubating the plates, you observe that plate A has only a few colonies, while the others all h | Bacteria in the patient's sample are susceptible to antibiotic A but not B, C, and D |
| How does an antibiotic act as a selective agent in promoting bacterial resistance? | Bacteria with a random mutation that allows resistance to that antibiotic are able to survive exposure and reproduce, passing the resistance mutation on to subsequent generations of bacteria. |
| Two agar plates, one containing the antibiotic streptomycin and one without antibiotics, are inoculated with E. coli. After incubation, the streptomycin negative plate has many bacterial colonies, while the streptomycin positive plate has only a few colon | the antibiotic streptomycin |
| Which of the following is the source of new, novel alleles in a population? | mutation |
| If you assume that 100 bacteria were plated on each plate, what percentage of the bacteria on plate B were resistant to ampicillin? | 3% |
| Bacteria from three different cultures were plated on agar plates containing ampicillin, an antibiotic. The results can be seen below. In which of the cultures were 100% of the bacteria susceptible to the antibiotic? | Plate C |
| If you wanted to grow up a large quantity of streptomycin resistant E. coli, what would you do next? | Pick a colony of bacteria from the streptomycin positive plate and grow it on a streptomycin positive plate. |
| E. coli bacteria were spread on both agar plates and incubated for 24 hours. What does this image tell you about the bacteria? | The bacteria were susceptible to streptomycin. |
Created by:
Jen2pen
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