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Genetics

Chapter 7

QuestionAnswer
In 1928, Griffith found that injecting which strains of Pneumococcus caused the mouse to die? A) living RII B) heat-killed type SIII C) heat-killed type RII D) heat-killed type SIII and living type RII E) heat-killed type RII and living type RII D
The process by which Pneumococcus transfers DNA between living type RII and heat-killed type SIII cells is known as A) transformation. B) replication. C) transduction. D) ligation. E) conjugation. A
What treatment of heat-killed SIII bacteria extract resulted in the mouse living? A)destroying SIII lipids and polysaccharides B)destroying SIII DNA with DNase C)destroying SIII RNA with RNase D)destroying SIII proteins with protease E)control group B
In the Hershey-Chase experiment, what was labeled by growing bacteriophage in 32P-containing medium? A) ghost phage particles B) proteins C) lipids D) DNA E) RNA D
Which of the following are classified as pyrimidines? A) adenine and thymine B) guanine and cytosine C) adenine and guanine D) thymine and cytosine E) adenine and uracil D
Bond formed between the hydroxyl group of one nucleotide and the phosphate group of an adjacent nucleotide, forming the sugar-phosphate backbone of DNA? A) glycosidic bond B) phosphodiester bond C) ester linkage D) hydrogen bond E) ionic bond B
What is the difference between a nucleotide and a nucleoside? A nucleoside with with a phosphate ester linked to the sugar is a nucleotide.
What types of bonds are formed between complementary DNA bases? A) glycosidic bonds B) phosphodiester bonds C) covalent bonds D) hydrogen bonds E) ionic bonds D
If complementary DNA strands were arranged in a parallel manner, what would you expect to see? Charges of complementary nucleotides would repel and no hydrogen bonds would form.
What is one difference between DNA replication in bacteria versus eukaryotes? Eukaryotic chromosomes have many origins of replication,while bacteria have only one origin of replication.
During DNA replication in E. coli, what is the role of DnaA? DnaA bends DNA, hydrolyzing the hydrogen bonds in the 13-mer region of oriC and creating an open complex.
SSB isn't present during DNA replication what would u expect to see? C)Helicase activity inhibited so DNA strands cant be separated E)SSB prevents reannealing of the separated strands, so strands would quickly reanneal and DNA replication cannot proceed E
Created by: cac082
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