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The Prime Factors

Principles of Radiographic Imaging 5th Edition Chapter 11

QuestionAnswer
An increase in kVp by 15% that causes doubling in exposure and vice versa 15 Percent Rule
A direct relationship is necessary to compensate for the changes in intensity and film density film density Direct Square Law
A direct square law, mAs must increase when distance increases and vice versa in order to maintain image receptor exposure Exposure Maintaince Formula
A measurement of x-ray tube current, the number of electrons crossing the tube from cathode to anode per second Milliamprage(mA)
The product of tube current(mA) and exposure time(s) Milliamprage Per Second(mAs)
The ability of the x-ray to pass through structures and tissues Penetrability
Factors related to x-ray emission that are under direct control of the radiographer; Milliamprage(mA), kilovoltage(kVp), and distance(d) Prime Factors
The density of an x-ray should remain unchanged as long as the intensity and duration of the x-ray exposure remains unchanged Reciprocity Law
A measurement of the penetrating ability of the x-ray beam X-Ray Quality
A measure of the number of x-ray photons in the useful beam X-Ray Quantity
What are the three prime factors that affect x-ray emmision? Milliamprage(mA), kilovoltage(kVp), distance(d)
What is the unit of measurement for x-ray quantity? Roentgen(R)
Define ampere The unit of current, also known as amp
What is the relationship between mAs and density/IR exposure? Exposure is directly proportional to mAs, mAs is used as the primary controller of radiographic film density and image receptor exposure
What effect does increased kVp have on the speed and energy of the electrons in the x-ray tube? Increasing the kVp will cause an increase in the speed and energy of the electrons applied across the x-ray tube applied across the x-ray tube.
What is the relationship between kVp and density/IR exposure? kVp is the primary controller of the differences in densities/IR exposures
State the inverse square law. The intensity of radiation at a given distance from a point source is inversely proportional to the square of the distance
What is the relationship between distance and density/IR exposure? X-ray intensity will decrease as the distance from the tube is increased
Created by: Dallas1856