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Principles of Radiographic Imaging 5th Edition Chapter 11

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Question
Answer
An increase in kVp by 15% that causes doubling in exposure and vice versa   15 Percent Rule  
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A direct relationship is necessary to compensate for the changes in intensity and film density film density   Direct Square Law  
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A direct square law, mAs must increase when distance increases and vice versa in order to maintain image receptor exposure   Exposure Maintaince Formula  
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A measurement of x-ray tube current, the number of electrons crossing the tube from cathode to anode per second   Milliamprage(mA)  
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The product of tube current(mA) and exposure time(s)   Milliamprage Per Second(mAs)  
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The ability of the x-ray to pass through structures and tissues   Penetrability  
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Factors related to x-ray emission that are under direct control of the radiographer; Milliamprage(mA), kilovoltage(kVp), and distance(d)   Prime Factors  
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The density of an x-ray should remain unchanged as long as the intensity and duration of the x-ray exposure remains unchanged   Reciprocity Law  
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A measurement of the penetrating ability of the x-ray beam   X-Ray Quality  
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A measure of the number of x-ray photons in the useful beam   X-Ray Quantity  
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What are the three prime factors that affect x-ray emmision?   Milliamprage(mA), kilovoltage(kVp), distance(d)  
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What is the unit of measurement for x-ray quantity?   Roentgen(R)  
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Define ampere   The unit of current, also known as amp  
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What is the relationship between mAs and density/IR exposure?   Exposure is directly proportional to mAs, mAs is used as the primary controller of radiographic film density and image receptor exposure  
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What effect does increased kVp have on the speed and energy of the electrons in the x-ray tube?   Increasing the kVp will cause an increase in the speed and energy of the electrons applied across the x-ray tube applied across the x-ray tube.  
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What is the relationship between kVp and density/IR exposure?   kVp is the primary controller of the differences in densities/IR exposures  
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State the inverse square law.   The intensity of radiation at a given distance from a point source is inversely proportional to the square of the distance  
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What is the relationship between distance and density/IR exposure?   X-ray intensity will decrease as the distance from the tube is increased  
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