Question | Answer |
Step 1 of Glycolysis | 2 ATP's are spent splitting a 6 carbon glucose to form two, 3-carbon G3P molecules |
Step 2 of Glycolysis | the G3P's are rearranged to form two 3-carbon pyruvate molecules. 4 ATP's and 2 NADH molecules are produced. |
Step 1 of the Krebs Cycle | Acetyl Co-A is added to a 4 carbon molecule (oxaloacetate) to make a 6 carbon molecule (citrate) |
Step 2 of the Krebs Cycle | 1 carbon is removed to form CO2 and produces 1 NADH (5 carbons left) |
Step 3 of the Krebs Cycle | Another carbon is removed and forms CO2. This prodcues 1 NADH and 1 ATP molecule (4 carbons left) |
Step 4 of the Krebs Cycle | 1 FADH2 and 1 NADH are produced turning the molecule back into 4 carbon oxaloacetate |
Step 1 of the Electron Transport Chain | NADH and FADH2 drop off their electrons at the electron transport chain |
Step 2 of the Electron Transport Chain | As electrons pass down the chain hydrogen is pumped into the inter membrane space creating a concentration gradient |
Step 3 of the Electron Transport Chain | Oxygen acts as a final electron receptor and bonds with 2 hydrogen ions to form water (waste product) |
Step 4 of the Electron Transport Chain | Hydrogen passes back into the matrix via ATP synthase. The energy produced by this passing allows ATP synthase to make 34 ATP molecules. |
Transition step before the Krebs Cycle | Pyruvate is changed into Acetyl Co-A by removing 1 carbon. This produces 1 NADH and 1 CO2. |
Step 5 of the Krebs Cycle | Oxaloacetate is added to another Acetyl Co-A and the krebs cycle turns a second time. |