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Limited Operator

QuestionAnswer
When were X-rays discovered? Novemeber 8, 1895
Who discovered X-rays? Wilhelm Conrad Roentgen
Largest radiologic science professional organization - ASRT
Establishes standards and examinations necessary to certify radiologic technologists - ARRT
National organization that formally conducts the accreditation of schools of radiologic technolgy - JRCERT (Joint Review Committee on Education in Radiologic Technology
LXMO Limited X-ray Machine Operator - the scope of practice is limited compared to registered techonologists
Physicians that specialize in interpreting radiographs and preform special imaging procedures - Radiologist
The source of the X-ray Beam - X-ray Tube
The x-ray tube is surrounded by a lead-lined ? Tube Housing
Cross section of the x-ray beam at the point where it is used is called ? the radiation field
An imaginary line in the center of the x-ray beam and perpendicular to the long axis of the X-ray beam - Central Ray
"Unseen" Image Latenet Image
Absorbtion of the X-ray Beam Attenunation
Radiation out side the body that has less engery but is hard to control - Scatter radiation
Causes unwanted exposure to the films and anyone in the room - Scatter radiation
Consists of the x-ray film and film holder IR (Image Receptor)or Cassette
A filmless system that uses digital format with computer technology CR or Computed Radiography
A box like device attached under the tube housing that allows variation in the size of the raditaion field. Collimator
A postition that allows the head to be lowered at least 15 degrees Trandelenburg Position
An oscilating grid under the table top Bucky
T or F The Primary X-ray Beam originates at a tiny point within the x-ray tube True
Unit that represents the rate at which x-rays are produced - mA or Milliamperage
The formula for determining mAs mA x seconds = mAs
Determine the mAs of an exposure made using 300 mA and 0.4 sec 300 mA x .04 sec = 120 mAs
Calculate the exposure time of 50 mA and 40 mAs - 40 mAs / 50 mA = .8 secs
Calculate the mA for the following exposure - 100 mAs and .5 sec 100 mAs / .5 sec = 200 mA
Distance in inches between the radiation source in the x-ray tube and the imaging plane SID or Source to Image Distance
T or F - Raditation intensity is inversly proportional to the square of the distance - TRUE
T or F - kVp is not a useful adjustment for relativly small variations from normal technique False - kVp IS a useful adjustment for realativly small variations from normal, because large changes in kVp cause significant alterations in appreance.
Beloe 85 kVp, and adjustment of ______ will compensate for small changes in part size - 2 kVp/cm
Above 85 kVp, and adjustment of ________ is necessary 3 kVp/cm
For a 2 cm increase in patient part size, increase the mAs by ________% 30 (multiply the mAs by 1.3)
For a 2cm decrease in patient part size, decrease the mAs by _________ % 20 (multiple the mAs by 0.8)
kVp is ________ to lengthen the scale of contrast - increased
Increasing kVp has these effects - decreases contrast, increases latitude, and creates a GRAYER image
kVp is ________ to shorten the scale of contrast - decreased
Decreasing kVp has this effect - increased contrast, more black and white appearance
Created by: airbear56