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Transcription Part 1
Transcription I
Question | Answer |
---|---|
How does RNA polymerase read the template strand? | In the 3' to 5' direction and produces a transcription in the 5' to 3' direction identical in the the sequence to the bottom coding strand |
What does unwinding DNA do? | Create a transcription bubble (Chromatin has to undergo chromatin remodeling) |
What does SSB do? | Prevents reannealing |
What needs to be recognized for transcription to occur and what needs to be present in the proceeding nt? | Promoter has to be recognized and a 3' OH needs to be on the proceeding nt for continued polymerization |
What happens to the incoming nucleoside triphosphate? | At the alpha, the 3'OH undergoes a nucleophillic attack of incoming NTP. |
After reaction occurs what is released? | Pyrophosphate (PPi) which almost instantaneously cleaved into 2 inorganic phosphates (Pi) thereby driving the reaction irreversibly |
What does the prokaryotic system transcription require? | Requires assembly of a # of polypeptide chains |
E. Coli RNA polymerase subunits | alpha=holoenzyme assembly; initiation. beta=Nucleotide binding; chain initiation & elongation, 5'-3' RNA synthesis. b'=binding to DNA template(strong affinity for DNA, helps b latch on) sigma=recog & binding to promoters; open promoter complex |
When can sigma be discarded? | At point of initiation, only core needed for elongation & termination |
RNA polymerase I | 14 subunits, nucleolus, produces rRNA precursors, resistant to inhibition by alpha-amanitin. |
RNA polymerase II | 12 subunits, nucleus, precursor to mRNA, sensitive to alpha-amanitin |
RNA polymerase III | 17 subunits, nucleus, synthesizes 5SrRNA, tRNA & small RNAs, moderated sensitivity to alpha-amanitin |
What do all 3 RNA polymerase have in common? | All 3 have a common large subunit (lots of resemblance to B & B' of Pro) |
Large subunit of RNA polymerase II | At the C terminus domain, there is a repeat 7-amino acid peptide: CTD domain; 2 large subunits=claw like, small subunits cluster on the periphery of large subunits |
Termination rho-independent | rho-independent: does not require rho factor, intrinsic secondary structure (stem-loop) that is created by newly synthesized RNA. Induces RNA pol to pause. Stem loop is rich in GC residues followed by poly U tract. |
Inhibitors of Transcription | Actinomycin D: Both Pro & Euk, intercalator b/w G & C. Rifampicin: blocks B subunit in Pro system. Alpha-amantinin: inhibits RNA pol II in Euk |
What does the 5' cap structure enable in Euk? | Enables mRNA to be recognized by the initiation factor eIF-4F. Cap contributes to the integrity & stability of mRNAs by protecting the 5' ends from attack by phosphatases & %' exonucleases |
Describe the process of polyadenylation | Poly A tail is added post-transcriptionally to 3' end of Euk mRNA by poly A polymerase. Site of polyadenylation is determined by the hexanucleotide AAUAAA. |
What does polyadenylation do? | Enhances mRNA stability by protecting it against degradation mediated by 3' exonuclease. It has been postulated to aid in mRNA transport from nucleus to cytoplasm (histone mRNAs lack a poly A-tail) |
RNA editing | Introns are removed |
How is rRNA transcript in Prokaryotes synthesized? | As a longer precursor of 30S: contains rRNA-16S, 23S & 5S rRNA |
How is rRNA transcribed in Eukaryotes? | 35S & 47S (larger precursor)- 18S, 28S and 5.8S |
How is tRNA spliced? | BY RNase P which is an endonuclease that recognizes tertiary structures of primary transcript to effect change at 5' end of the tRNA precursor. |
What does mature tRNA contain? | CCA at the 3' end |
What happens if CCA is in sequence and not at 3' end? | RNase D is required to cleave til CCA is at the 3' end |
What happens if CCA is not present? | It may be generated post-transcriptionally by the enzyme tRNA nucleotidyl transferase in a reaction that uses 2 molecules of CTP & one molecule of ATP |