Quantitative
Quiz yourself by thinking what should be in
each of the black spaces below before clicking
on it to display the answer.
Help!
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| show | researcher manipulates/researcher can assign you/ cause (not result)
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| dependent variable | show 🗑
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| correlation | show 🗑
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| population | show 🗑
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| sample | show 🗑
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| show | numerical summary characteristics of a population
stuff you can measure about a population
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| show | numerical summary of characteristics of a sample
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| nominal scale (scale of measurement) | show 🗑
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| ordinal scale (scale of measurement) | show 🗑
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| show | equal intervals btwn numbers
rank & equal distance
zero isn't true zero, its a point on a scale
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| ration (scales of measurement) | show 🗑
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| frequency distribution | show 🗑
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| rules of graphing | show 🗑
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| bargraph | show 🗑
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| histogram | show 🗑
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| grouped frequency distribution | show 🗑
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| central tendency | show 🗑
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| mode | show 🗑
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| show | score that separates top half of group of scores from bottom half
normal curve-median & mode in same place
*data has to be in order
middle score
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| show | score at or below which a given percentage of the scores lie
50th percentile: 50% of score are below that score
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| mean | show 🗑
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| mean properties | show 🗑
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| show | aka standard scores
the deviation of the raw from the mean in standard deviation units
z=raw score(x)-(mean)/SD
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| show | the probability of event occurring is proportion of times event would occur if chance of occurrence were infinite
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| statistical hypothesis | show 🗑
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| show | 1. each event independent from each other/ stand alone. necessary for simple probability
2. dice or coin dont have memory and cant remember or keep track
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| gamblers phallacy | show 🗑
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| show | mutually exclusive random events
compute the probability of one OR the other occurring
P(A or B)= PA + PB
2 of spaids or 3 of clubs
1/52 + 1/52 = 2/52 = 1/56
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| show | probability of 2 or more independent events occurring is the product of individual probabilities
P rolling 2 ones (snake eyes)
(1/6) (1/6) = 1/36
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| show | *conditional probability
drawing card and holding onto it
draw ace and draw another one
(4/52)(3/51)=1/221= .0045= .45%
probability of second dependant on first
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| confidence interval | show 🗑
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| interval | show 🗑
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| sampling distribution of mean | show 🗑
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| sampling distribution of mean (rules) | show 🗑
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| show | the more samples you get, the more the frequency graphs will look like normal curve
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| t-score | show 🗑
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| variable | show 🗑
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Created by:
frankiegym
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