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SHAPES AND MOLE7

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Question
Answer
C60 SOMETIMES   CALLED A BUCKYBALL.  
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C70 MOLECULES ARE SHAPED LIKE   A RUGBY BALL HAS 25 HEXAGONS.  
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EVAPORATION OF A MOLECULE OF C60 C70 IN BENZENE PRODUCES   RED CRYSTALS.2 C60 BUCKY BALLS CAN BE JOINED BY A FOUR MEMBERED CARBON RING TO MAKE C120.  
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C60 C70 ARE   . FULLERENES  
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C60 C70 ARE LIKE ALKENES COZ   ADDITION REACTIONS, WITH HYDROGEN AND HALOGENS ,C60 CAN BE POLYMERISED.  
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WHY CAN C60/70 BE IMPORTANT FORM MEDICINE   A ATOM/ION CAN BE TRAPPED BETWEEN CARBON BALLRADIOACTIVE ARGON-224 ATOMS ARE TRAPPED INSIDE C60 MOLECULES AND COATED WITH TUMOUR TARGETING ANTIBODIES =  
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INJECTED INTO CANCER PATIENT. THE TREATED C60 IS ABSORBED BY THE CANCER CELLS - THE RADON ATOMS EMIT ALPHA RAYS WHICH DESTROY THE CANCER BUT HAVE SHORT RANGE OF RAYS SO DOE’S HARM OTHER ORGANS.    
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WHY DOES C-60 WORK IN TREATING CANCER   IT’S ABSORBEDBY CANCER CELL. RADON EMMMITS ALPHA WHICH DESTROYS CANCER  
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CARBON NANOTUDES ARE   CYLINDER OF INTERLOCKING HEXAGONS OF CARBON ATOMS. ONE END SEALED WITH FULLERENE MOLECULE , THE RADIUS IS A FEW NANOMETERS.  
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WHY ARE NANOTIBES SO SLIM   THE RADIUS IS A FEW NANOMETERS/  
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NANOTUBES CAN BE USED TO   DELIVER DRUGS TO SPECIFIC PARTS OF THE BODY.  
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CLUSTERS OF CARBON NANOTUDES   ARE ONE HUNDRED TIMES AS STRONG AS STEEL WIRE –HAVE DELOCALISED ELECTRONS AND CAN CONDUCT ELECTRICITY.  
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SILICON HAS A   SILICON CARBIDE DIAMOND LIKE STRUCTURE – HAS 4 CARBON ATOMS SURROUNDED BY 4 SILICON ATOMS.  
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QUARTZ SIO2 IS A   GIANT ATOMIC LATTICE EACH SILICON BONDED TO 4 OXYGEN AND EACH OXYGEN HAS 2 SILICON.  
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ALL GIANT ATOMIC SUBSTANCES HAVE VERY HIGHER METING POINT COZ   COVALENT BONDS HAVE TO BE BROKEN WHEN -SOLID IS MELTED OR SUBLIMED.  
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DIAMOND AND GRAPHITE SUBLIME AT   OVER 3500DEGREES CELSIUS. AND QUARTS MELT AT 1610DEGREES CELSIUS.  
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GIANT ATOMIC SUBSTANCES ARE HARD BECAUSE   COVALENT BONDS, USEFUL AS ABRASIVES E.G. SANDPAPER COATED WITH GRAINS OF QUARTZ, ABRASIVE CARBORUNDUM IS MADE OF SILICON CARBIDE.  
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ABRASIVE CARBORUNDUM MADE OF   SILICON CARBIDE.  
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SIMPLE MOLECULES FORMED BY   N2 O2 S8,P4 ,HALOGEN IN GROUP 7 ALL DIATOMIC. FONPSCL.  
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FORCES BETWEEN ELEMENTAL ELEMENTS ARE   DISPERSION, THEY ALSO FORM SIMPLE MOLECULE STRUCTURES E.G. ALKANE , ALKENE , HALOGENOALKANES , HYDROGEN SUPLIDEH2S, PHOSPHORUS TRICHLORIDE PCL3 PHOSPHORUS PENTACHLORIDE AND SF6.  
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THE FORCES ARE DIPSPERISON IF   MOLECULE IS POLAR & PERMANENT DIPOLE DIPOLE.  
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MELTING AND BOILING INTERMOLECULAR FORCES ARE WEAK SO   SIMPLE MOLECULAR SUBSTANCES HAVE LOW MELTING AND BOILING TEMPS.  
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THE BOILING POINTS OF NOBLE GASES   INCREASE DOWN THE GROUP HELIUM LOWEST.  
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WHY DOES BP INCREASE DOWN A GROUP   BECAUSE OF DISPERSION FORCES. AND THE STRENGTH OF FORCES INCREASE AS... NUMBER OF ELECTRONS INCREASES.  
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BOILING TEMP OF ALKANES INCREASE AS THE NUMBER OF   CARBON ATOMS INCREASE,. THE LARGE MOLECULES HAVE MORE POINTS OF CONTACT MORE DISPERSION FORCES SO TOTAL DISPERSION FORCE IS GREATER.  
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MORE POINT OF CONTACT MEANS   MORE DISPERSION FORCES  
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DIPERSION FORCES INCREASE   AS NO OF ELECTRON INCREASE  
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THE BOILING POINTS OF HYDROGEN HALIDES HCL-HI, INCREASE DUE TO STRENGTH OF   DISPERSION FORCES INCREASES AS NUMBER OF ELECTRONS MORE. BUT H-F IS ANOMALOUS IT FORMS INTERMOLECULAR HYDROGEN BONDS.  
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H-F ,H2O,COOH ACIDS,NH3,AND ORGANIC AMINE ARE   HYDROGEN BONDED  
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FOR THEM TO BOIL MOLECULES MUST BE   SEPERAETED INVOLVES BREAKING THE HYDROGEN BONDS & DISPERSION FORCES.  
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