SHAPES AND MOLE2
Quiz yourself by thinking what should be in
each of the black spaces below before clicking
on it to display the answer.
Help!
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| 2 BOND PAIRS AND ONE LONE PAIR | BENT
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| SULFUR DIOXIDE O=S=O HAS | 4 OF THE 6 VALENCE ELECTRONS USED IN BONDING SO ONE LONE PAIR THE 3 ELECTRON PAIRS ARE IN A TRIGONAL PLANER POSITION , BUT IS DESCRIBED BY POSITION OF ATOMS AROUND SULFUR = BENT/V SHAPED.
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| SPECIES WITH 4 ELECTRONS | TETRAHEDRAL HAS 109.5 BOND ANGLES. E.G. METHANE CH4. FORMS 4 SIGMA BONDS ALL VALENCE ELECTRON IS USED IN BONDING = NO LONE PAIRS.
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| TO DRAW TETRAHEDRAL | THE DOTTED ONE TO THE LEFT AND TRIANGLE IN THE MIDDLE.
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| HOW ARE ALKANES BONDED | TETRAHEDRALLY BONDED SKELETAL FORMULA SHOWS ...BOND ANGLES BETTER.
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| SILICON IN GROUP 4- SO SIH4 SICL4 | TETRAHEDRAL
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| NH4+ AMMONIUM IS WHY | - 3 OF FIVE VALENCE ELECTRON IN NITROGEN USED TO FORM SINGLE COVALENT BONDS WITH HYDROGEN 2 USED TO FORM A DATIVE BOND WITH H+ ION. BOND PAIRS REPEL.
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| AL2CL6 IS WHY | 4 BOND PAIRS OF ELECTRON SURROUND EACH AL. SO 4 CHLORINE ATOMS ARRANGED IN A TETRAHEDRON AROUND THE ALUMINIUM. 109.5DEGREES.
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| SULFATE HAS | – 4 SIGMA AND 2 PI ALL SIX VALENCE ELECTRONS USED IN BONDING. – SIGMA BONDS REPEL EQUALLY =TETRAHEDRAL. TRIANGLE COMING OUT DOTTED COMING IN.
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| 3 BOND PAIRS AND ONE LONE PAIR | 4 PAIRS OF ELECTRONS ARE ARRANGED TETRAHEDRALLY AROUND CENTRAL ATOMS,- BUT IT IS PYRAMIDAL – LONE PAIR IS AT THE TOP.
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| AMMONIA MOLECULES SHAPE ARE | WHY PYRAMIDAL 5 VALENCE ELECTRONS IN GROUP 5 THE ELECTRONS ARE ARRANGED TETRA BUT ARE PYRAMIDAL.
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| WHEN DRAWING AMONIA DRAW | ONE ORDINARY LINE – ONE WEDGE, ONE DASHED. PYRAMIDAL
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| THE REPULSION BETWEEN LONE PAIR AND BOND PAIRS | IS GREATER THAN REPULSION BETWEEN JUST BOND PAIRS.
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| SO PYRAMIDAL BOND ANGLE ... | HAS 107 DEGREE ANGLE.
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| SULPHITE ION SHAPE SO32 IS... WHY | PYRAMIDAL – FORMS 2 SINGLE BONDS WITH 2 OXYGEN ATOMS , ONE DOUBLE BONDS WITH OXYGEN. SO ONLY 4 OF 6 VALENCE ELECTRONS USED. SO ONE LONE PAIR.
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| 2 BOND PAIRS AND 2 LONE PAIR IS | ARRANGED TETRAHEDRALLY, ONLY 2 ATOMS BONDED TO THE CENTRAL ATOM – IT IS BENT V SHAPED.
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| EXMPLE OF BENT IS | WATER 2 OXYGEN VALENCE ELECTRONS USED IN BONDING, SO 2 LONE PAIRS.
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| FOR BENT 2 BOND 2 LONE THE BOND ANGLE IS | 104.5 ANGLE. THE 4 ELECTRON PAIRS REPEL AT A MINIMUM REPULSION SO IT BENT.
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| IN ETHANOL THE OXYGEN ATOM | HAS 2 SIGMA AND 2 LONE PAIRS SO THE C-O-H IS 104.5. THE OTHER BONDS AND NORMAL TETRAHEDRAL.
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| 5 ELECTRONS PAIRS HAS | 5 BOND PAIRS NO LONE PAIRS, TRIGONAL BIPYRAMIDAL.
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| 5 ELECTRONS PAIRS HAS | POSITION OF MAXIMUM SEPARATION FORMS ONE PLANAR MOLECULE CALLED TRIGONAL BIPYRAMIDAL.
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| EXAMPLE OF TRIGONAL BIPYRAMIDAL | PHOSPHORUS PENTACHLORIDE,PCL5 HAS 5 BONDING ANGLE 90 AND 120 DEGREES.
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| DRAWING TRIGONAL BIPYRAMIDAL | THE TRIANGLE AND THE DOTTED LINES IS ON THE LEFT SIDE. THE RIGHT HAS 90 DEGREE ANGLE.
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| LONE PAIR LONE PAIR REPULSION GREATEST IN | TRIGONAL BIPYRAMIDAL
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| 6 ELECTRON PAIR’S SIX ELECTRON PAIRS REPEL TAKE UP | OCTAHEDRAL ARRANGEMENT. WITH 90 DEGREES BOND ANGLES
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| EXAMPLE OF 6 ELECTRON PAIRS | SF6. ALL VALENCE ELECTRONS USED.
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