Chem unit 1 pastpap2
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This question is about hexane, C6H14, and hex-1-ene, C6H12. What test would you use to distinguish between hexane and hex-1-ene Give the results of the test for each substance, | show 🗑
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show | Test : add (acidified) potassium manganate((VII)(solution)ALLOW potassium permanganate Result: no change with hexane/stays purple
And goes colourless / brown with hex-1-ene (1) OR
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show | Test : add alkaline potassium manganate((VII))(solution)(1) ALLOW potassium permanganate
Result: no change with hexane/stays purple and goes green with hex-1-ene (1)
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show | C=C restricts rotation/ C=C prevents twisting /C=C can’t rotate/ lack of free rotation round
C=C (so the groups can’t change position relative to the bond)
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show | Hex–2-ene has different groups on the C at each
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The value for the enthalpy change of combustion in this experiment is different from the value given in data books. Suggest TWO reasons for this difference | show 🗑
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A student suggested that the results would be more accurate if a thermometer which read to 0.1°C was used. Explain why this would not improve the accuracy of the result. A calculation is not required. | show 🗑
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C6H12(l) + H2(g) → C6H14(l) (i) What catalyst is used in this reaction? | show 🗑
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Explain why the values(standard enthalpy change) are so similar | show 🗑
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Chloroethae, C2H5Cl, can be made from either ethane or ethene.(i) What reagent and condition would be used to make chloroethane from ethane | show 🗑
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State the type of reaction and mechanism by which this reaction occurs | show 🗑
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show | Hydrogen chloride / HCl
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Which of making chloroethane has electrophilic addition a higher atom economy | show 🗑
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From ethene | show 🗑
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show | yield high as no di-, tri- etc substituted products form /only one product / no by-products OR no side reactions occur OR no C4 compounds can form.
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show | Energy for man materials/lifetime of product/how often need replaced /metal rusts/plastic more easily punctured etc • ease of recycling/steel an excellent recyclable material/consequences of disposal/is it biodegradable? from a non-renewable resource?
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show | C2H5 and the molecular formula C4H10.
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Avogadro constant 6.0 × 1023 mol–1. Therefore the number of atoms in 1 mol of carbon dioxide is | show 🗑
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show | / by 4 +412kjmol-1
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show | C2H6 + Cl2 --> C2H5Cl + HCl.
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The role of the UV radiation in the reaction is to | show 🗑
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