Embed Code - If you would like this activity on your web page, copy the script below and paste it into your web page.

Normal Size Small Size show me how

Normal Size Small Size show me how

# Maths

Question | Answer |
---|---|

Integrate dy/dx= (x + 4)(x - 2) | y = 1/3x^3 + x^2 - 8x |

12x2 - x - 6 | (3x + 2)(4x - 3) |

2^x = 24 | log2^x = log24 xlog2 = log24 x = log24/log2 x = 4.585 |

The number of bacteria in a food medium being studied in a lab t minutes after observation is given by: N= 12 * 10^3+0.02t What is the initial number of bacteria present? | N= 12000 |

The number of bacteria in a food medium being studied in a lab t minutes after observation is given by: N= 12 * 10^3+0.02t After how many minutes will the food medium contain 25000 bacteria?? | t= 15.94 minutes |

Differentiate 3x^2 + 2x - 6 | dy/dx= 6x + 2 |

Find the equation of the curve that passes through (2,6) and has a gradient function dy/dx= 3x^2 - x + 2 | y= x^3 - 1/2x^2 + 2x - 4 |

The distance, s, in meters, traveled by a particle is given by the formula s= 80t - 12t^2. Find the expression for velocity, and hence find the initial velocity. | v= 80 - 24t initial velocity= 80m/s |

A rock is thrown vertically with an initial velocity of 40m/s from a point 5m above ground. The velocity of the rock after t seconds is given as: v= (40 - 10t) m/s Find s (t) | s (t)= 40t - 5t + c s (t)= 40t - 5t + 5 |

A rock is thrown vertically with an initial velocity of 40m/s from a point 5m above ground. The velocity of the rock after t seconds is given as: v= (40 - 10t) m/s Find the maximum height | When s'(t)=0, t= 4seconds s(t)= 85m |

Simplify (2x^4)^3 * 3x^2 | 8x^12 * 3x^2 = 24x^14 |

Factorize x^2 - 6x + 16 | (8 - x)(x + 2) |

Factorize 2x^2 - 2x - 12 | 2(x - 3)(x + 2) |

Simplify 2x+6/x+3 | 2 |

Solve 12x - 11 = 15x + 10 | x = -7 |

Solve x^2 + 6x + 2 | x= -5.631, -0.369 |

Find dy/dx when y= x^2 + 4x - 7 at the point (2,5) | dy/dx= 2x + 4 - 4 OR dy/dx= 2x |

Created by:
RubySwann