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Chem 116 Post Exam 3
| Question | Answer |
|---|---|
| Oxidation | loss of electrons |
| Reduction | gain of electrons |
| Oxidation agent | species that is reduced |
| Reduction agent | species that is oxidized |
| For an atom in elemental form, what is the oxidation number? | 0 |
| What determines the concentration of an oxidizing agent from the known concentration of the reduction agent? | redox titration |
| Generally, metal is the ______ agent and nonmetal is the ______ agent | reducing; oxidizing |
| Voltaic cell: | uses a spontaneous reaction to generate electrical energy (delta G>0) |
| Electrolytic cell: | uses electrical energy to drive nonspontaneous reaction (delta G<0) |
| Oxidation half reaction occurs in the... | anode |
| Reduction half reaction occurs in the... | cathode |
| Anode has _______ charge; Cathode has _______ charge | negative; positive |
| Joins half cells allowing ions to flow through both compartments and complete the circuit | salt bridge |
| Cell potential (Ecell) | Electrical potential between the two electrodes (voltage) |
| For a spontaneous process, Ecell... | >0 |
| standard Ecell | =standard E (cathode/reduction) - standard E (anode/oxidation) |
| As E(half cell) increases, oxidizing agent ________; reducing agent __________ | increases; decreases |
| As E(half cell) decreases, oxidizing agent ________; reducing agent __________ | decreases; increases |
| Self contained voltaic cells arranged in a series so that their individual voltages are added | batteries |
| As cell operates, it's potential ___________ | decreases |
| In electrolysis of pure molten salts, __________ will be reduces and __________will be oxidized | cation; anion |
| Positive electrode potential corresponds to _______ | reduction |
| Negative electrode potential corresponds to _______ | oxidation |
| Steps to balance redox reactions: | 1. Separate into half reaction 2. Balance atoms other than O and H 3. Balance O by adding H2O 4. Balance H by adding H+ 5. Balance charges with e- 6. Multiply each half reactions so that e- are equal |