Save
Busy. Please wait.
Log in with Clever
or
show password
Forgot Password?
Don't have an account?  Sign up 
Sign up using Clever
or
Username is available taken
show password


Make sure to remember your password. If you forget it there is no way for StudyStack to send you a reset link. You would need to create a new account. Your email address is only used to allow you to reset your password. See our Privacy Policy and Terms of Service.

Already a StudyStack user? Log In

Reset Password
Enter the associated with your account, and we'll email you a link to reset your password.
focusNode
Didn't know it?
click below
 
Knew it?
click below
Don't Know
Remaining cards (0)
Know
0:00
edit
Embed Code - If you would like this activity on your web page, copy the script below and paste it into your web page.

  Normal Size     Small Size show me how

CHM130 Lesson 8 AYL

QuestionAnswer
When iron is produced from hematite, the following reaction occurs. How many grams of Fe are obtained from 50.0 g of hematite in this process? Fe2O3 + 3CO ® 2Fe + 3CO2 You have to calculate the percentage of iron in the iron oxide: (mmFe) 55.84 /(mmFe2O3) 159.68 *2 (because you produce 2 mols of Iron) *100 = 69.94% 50g*69.94/100 = 34.94g obtained of Iron
If 132.0 g CuO is reacted with 5.000 g H2, what mass of Cu would be prepared by the following reaction? CuO + H2 ® Cu + H2O moles CuO = 132.0 g / 79.5454 g/mol = 1.66 moles H2 = 5.000 g/ 2.106 g/mol = 2.48 ( in excess) moles Cu = 1.66 mass Cu = 1.66 mol x 63.546 g/mol =105.5 g
Sugar cane produces sucrose (C12H22O11) from water and carbon dioxide through photosynthesis: 12CO2 + 11H2O ® C12H22O11 + 12O2 If the reaction consumes 30.0 g of carbon dioxide and produces 6.84 g of sucrose, what is the percent yield? Molar mass CO2 = 12.011+15.99*2 = 44.009g/mol Molar mass C12H22O11 = 12.001*12+1.008*22+15.999*11= 342.297g/mol 30g CO2 = 30/44.009 = 0.682mol 0.682mol CO2 will produce : 0.682/12 = 0.0568mol sucrose 0.0568mol sucrose = 0.0568*342.297 = 19.445g su
Balance the following chemical equations: CaCl2 + Na2SO4 ® CaSO4 + NaCl CaCl2 + Na2SO4 = CaSO4 + 2 NaCl
Al + O2 ® Al2O3 4 Al + 3 O2 = 2 Al2O3
KI + Cl2 ® KCl + I2 2 KI + Cl2 = 2 KCl + I2
The heads of matches are made with P4S3. This material is made by heating a mixture of red phosphorus and sulfur: 8P4 + 3S8 ® 8P4S3 If a match company uses 5435 grams of phosphorus (P4) with an excess of sulfur, how many grams of P4S3 can be made? P4 MW = 123.88 g/mol S8 MW = 256.48 g/mol P4S3 MW = 220.06 g/mol (5435 g P4 / 123.88 g/mol) = 43.87 moles P4 43.87 moles P4 x 220.06 g/mol P4S3 = 9654.03 g P4S3
Flashlights use magnesium because of the bright light that is formed when it burns. How many grams of magnesium oxide will be produced if 0.432 g Mg is reacted with 0.130 g O2? 2Mg + O2 ® 2MgO 0.00876 mol MgO x (40.31 g MgO / 1 mol MgO) = 0.353 g Mg [Cancel moles of Mg] The reaction yields approximately 353 milligrams of magnesium oxide.
Created by: jessicayanes
Popular Chemistry sets

 

 



Voices

Use these flashcards to help memorize information. Look at the large card and try to recall what is on the other side. Then click the card to flip it. If you knew the answer, click the green Know box. Otherwise, click the red Don't know box.

When you've placed seven or more cards in the Don't know box, click "retry" to try those cards again.

If you've accidentally put the card in the wrong box, just click on the card to take it out of the box.

You can also use your keyboard to move the cards as follows:

If you are logged in to your account, this website will remember which cards you know and don't know so that they are in the same box the next time you log in.

When you need a break, try one of the other activities listed below the flashcards like Matching, Snowman, or Hungry Bug. Although it may feel like you're playing a game, your brain is still making more connections with the information to help you out.

To see how well you know the information, try the Quiz or Test activity.

Pass complete!
"Know" box contains:
Time elapsed:
Retries:
restart all cards