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Complex numbers

5/(5+8i) multiply both numerator & denominator by (5-8i)= (25-40i)/25-64i^2. change i^2 to -1 and simplify. answer 25/89 -40i/89
(5a+2b) - (8a -3b) =5a+2b-8a+3b, which equals -3a+5b
what does (i)^2 equal? -1
(a+b)(a-b) a^2-b^2
what is the square root of -1 i
(2a-3b) - (a-6b) a+3b
(9+7i)/(1+i) multiply both numerator and denominator by (1-i) and factor out...answer is 8-i
(7-i)(4-7i)/(4+7i)(4-7i) 21/65 -53i/65
what is the complex conjugate of (a+bi)? (a-bi)
7/3i - 7i/3
Created by: robinb919