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# Application Problems

### MTH005 Ch 3 Standard Format of Application Problems

Type of Application Problem | General Form of the Equation |
---|---|

Things of Value | (# of items times cost or value per item) + (# of items times cost of value per item) = Total value |

Mixtures | (Quantity1 times Unit Cost1) + (Quantity2 times Unit Cost2) = Total Quantity Times Mixture's Unit Cost |

Dual Investments | (Principal1 times Interest Rate1) + (Principal2 times Interest Rate2) = Total Interest |

Liquid Solutions | (Amount of Solution1 times %1) + (Amount Solution2 times %2) = Total Amount of mixture times mixture's % |

Distance, rate, time | (Rate1 times Time1) + (Rate2 times Time2) = Total distance |

Piece Lengths | Length of Piece1 + Length of Piece2 = Original Total Length |

Basic Number Problems | 1st sentence or phrase describes the #s. 2nd sentence or phrase is translated into the equation using the representations determined by the 1st sentence or phrase |

Percents in Business | Percent times Base = Resulting Amount; Identify P, B, & A in the problem; set up an equation; & solve |

3 Consecutive Integers | x; x + 1; x + 2; Example: If x = 3 then x + 1 = 4 and x + 2 = 5. Three Consecutive Integers 3, 4 & 5 |

3 Consecutive Even Integers | x; x + 2; x + 4; Example: If x = 4 then x + 2 = 6 and x + 4 = 8. Three Consecutive Even Integers 4, 6 & 8 |

3 Consecutive Odd Integers | x; x + 2; x + 4; Example: If x = 7 then x + 2 = 9 and x + 4 = 11. Three Consecutive Odd Integers 7, 9 & 11 |

1st Integer is Even; Next 2 Consecutive Odd Integers | x + 1; x, + 3; Example: If x = 4, then x + 1 = 5 and x + 3 = 7. Four is an even integer, and 5 & 7 are the next 2 Consecutive Odd Integers |

1st Integer is Odd; Next 2 Consecutive Even Integers | x + 1; s + 3; Example: If x = 3 then x + 1 = 4 and x + 3 = 6. Three is an Odd Integer, and the next 2 Consecutive Even Integers are 4 & 6 |

Created by:
powens