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Math 11
SLS - Math 11 - Ch 5.1-5.3 - Function Notation
| f(x)=2x-3, g(x)=x^2 | Answer |
|---|---|
| f(3)+2g(-1) | 5 |
| (f+g)(x) | = x^2 + 2x - 3 |
| (f-g)(x) | -x^2 + 2x - 3 |
| (fg)(x) | 2x^3 -3x^2 |
| (f/g)(x) | = (2x - 3)/(x^2) restriction: x doesn't equal 0 |
| When do you have to list restrictions? | Whenever there's an x on the bottom of a fraction. Sometimes teachers will NOT take off marks. But you're safest to write it each time. |
| f(g(x)) | 2x^2 - 3 |
| f(f(x)) | 4x - 9 |
| g(g(x)) | x^4 |
| (fg)(-3) | -81 |
| f(f(0)) | -9 |
| (g/f)(4) | 16/5 |
| the inverse of f(x) | (x + 3) / 2 |
| the inverse of g(x) | square root of x |
| What are the steps to prove whether or not f(x) and g(x) are inverses of eachother? | Plug each function into the x variable of the other. If both simplify to x, they are inverses. |
Created by:
slscarrie
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