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# Module 4

### Variation & Problem Solving

Question | Answer |
---|---|

If y varies directly as x, find the constant of variation and direct variation equation: y is 5 and x is 30 = | y = kx,Substitute y and x in the equation, 5 = k.30; k = 5/30 ; k = 1/6. Substitute k in the direct variation equation = y = 1/6x. |

Direct Variation : y = 6 when x is 4 = | y = kx,Substitute y and x in the equation, 6 = k.4; k = 6/4 ; k = 3/2. Substitute k in the direct variation equation = y = 3/2x. |

Direct Variation: y = 0.2 when x is 0.8 = | y = kx,Substitute y and x in the equation, 0.2 = k.0.8; k = 0.2/0.8 ; k = 0.25. Substitute k in the direct variation equation = y = 0.25x |

When y varies inversely as x or y is inversely proportional to x, find the constant of variation and inverse variation equation: y = 6 when x = 5 = | y = k/x,Substitute y and x in the equation, 6 = k/5; k = ; k = 30. Substitute k in the inverse variation equation = y = 30/x. |

Inverse Variation: y = 0.2 when x = 0.7 = | y = k/x,Substitute y and x in the equation, 0.2 = k/0.7; k = ; k = 0.14. Substitute k in the inverse variation equation = y = 0.14/x. |

Inverse Variation: y = 1/8 when x = 16 | y = k/x,Substitute y and x in the equation, 1/8 = k/16; k = ; k = 2. Substitute k in the inverse variation equation = y = 2/x. |

y varies directly as square of x. If y is 24 when x is 2 find the constant of variation and variation equation? | y = kx^2 24 = k. 2^2 24 = 4k k = 6 Constant of variation is 6 and Variation Equation is y = 6x^2 |

Created by:
Sushma