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# Alg I Substitution

### Shows how to substitute or plug in for the variables X,Y in different equations.

Question | Answer |
---|---|

Y = X + 1 Y = 2X - 1 | 2,3 |

2Y = x + 3 X = Y | 3,3 |

X - Y = 1 X = 1/2Y + 2 | 3,2 |

Y = 3X + 1 X = 3Y + 1 | 7,2 |

Y = 1/2X + 4 2Y + 2X = 2 | -2,3 |

M = 5P + 8 M = 10P + 3 | 1,13 |

X + Y = -4 X - Y = 2 | -1, -3 |

X + Y = 10 Y = X + 8 | 1,9 |

3X + Y = 5 4X - 7Y = -10 | 1,2 |

X - 2Y = -10 3X - Y = 0 | 2,6 |

X + 3Y = 2 -X + 2Y = 3 | -1,1 |

Y - 2X = -5 3Y - X = 5 | 4,3 |

-X + Y = 1 2X + Y = 2 | -1,0 |

2X + 2Y = 3 X - 4Y = -1 | 1,1/2 |

3X - Y = 2 6X - 2Y = -8 | No Solution |

2x - y = -4 6x - 3y = -12 | Infinitely Many Solutions |

H = 6G - 4 H = -3G + 28 | 20,4 |

Y = 3X + 8 Y = 2X + 5 | -3,-1 |

6x + 2y = -2 4x + y = 1 | 2, -7 |

3x + 2y = 6 x + 2y = -6. | 6,6 |

5x - 4y = 9 x - 2y = -3 | 5,4 |

x + 3y = 5 4x + 5y = 13 | 2,1 |

x + 3y = 8 2x - y = 9 | 5,1 |

y = 2x 5x - y = 8 | 4,8 |

y = 2x y = -6x + 4 | 2,4 |

Created by:
MeganBoyd