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phys exam, lecture 3
| Question | Answer |
|---|---|
| at rest what's the mL of O2 needed for the average person | 3.5mL/kg/min |
| how many calories are in 1L of O2 | 5kcals |
| how do you calculate the cals needed per day? | 1. take relative VO2 to absolute (multiply VO2 by bodyweight) 2. convert mL to L (times .001) 3. convert L to cal ( times by 5) 4. need calories per hour (multiply by 60) 5. need calories per day (times 24) |
| parts of a graph showing VO2 | rest, O2 deficit, steady state, EPOC |
| O2 deficit | (O2 currently consuming vs what need @ steady state) 1. represents dif score (need VO2 of 30 to sustain exercise. currently consuming 15 mL/kg/min. still need 30. 30-15-15. 15 is the dif score). 2. represents anaerobic contribution |
| steady state ATP for long term exercise | (takes 1-4 mins to get) flat part of graph. demand is being met -sustainable over time (except in heat or supr high intensities) O2 demand & HR is stable. -anaerobic energy production makes up the dif from the dif score in O2 deficit = steady state |
| EPOC | (excess, post-exercise, oxygen, consumption) -recovery, repaying O2 deficit -excess O2 uptake above rest following exercise -how much extra O2 are we consuming post-exercise? -duration and intensity driven -could last 12-24 hours |
| 2 portions of EPOC | rapid portion- steep decline in O2 uptake following exercise. 2-3 mins post exercise (HR and respiration rate slowing down) slow portion- slow decline in O2 uptake following exercise. 30+ mins post exercise (resting VO2 going down). |
| EPOC= lactic acid clearance | 70% LA = oxidized- used as fuel by heart& skeleton 20% converted to glucose (gluconeogenesis = lactic acid-> glucose) 10% converted to amino acids light aerobic activity (a cooldown) will expedite lactic acid clearance process |
| what else happens during EPOC | lactate conversion to glucose restoration of blood O2 stores elevate body temp post-exercise elevation of HR and breathing (2-3 mins, rapid portion) -elevated hormones |