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MATH 416 Midterm2

MATH 416 Midterm 2

TermDefinition
Linear maps A linear map from V to W is a function T: V --> W satisfying additivity and homogeneity [ T(u+v) = Tu + Tv, T λu = λTu ]
Zero map For all u in V, Ou = 0
Identity map / operator For all u in V, Iu = u
Linear map lemma. Suppose v1,...,vn is a basis for V and w1,...wn is a basis for W. Then there exists a unique linear map T: V --> W such that Tvk = wk for k in (1,...,n). (A linear map is completely determined by its values on a basis.)
The sum of linear maps S and T (S + T) (u) = Su + Tu
The product λT (λT) (u) = λ (Tu)
For a linear map T and zero elements 0v and 0w in V and W, T(0v) = 0w (zero vectors map to zero vectors)
Null space (null(T)) For a linear map T, the null space is the set of vectors mapping to the zero vector. (All u in V such that Tu = 0). null(T) is a subspace of V.
Range (range(T)) For a linear map T, the range is the subset of W consisting of those vectors that are equal to Tu for some u in V. (Tu s.t. u in V). range(T) is a subspace of W.
Injectivity (one-to-one) A function T: V --> W is called injective if T(u) = T(v) implies u = v for all u, v in V.
A linear map T is injective iff A linear map T has null(T) = (0) iff
Surjectivity (onto) A function T: V --> W is called surjective if range(T) = W.
Fundamental theorem of linear maps. V is finite-dimensional and T is a linear map. dim(V) = dim(null(T)) + dim(range(T))
V, W are finite-dimensional vector spaces and T is a linear map from V to W. If dim(V) > dim(W), Then T is not injective.
Matrix representations and vector spaces The set of matrices with m rows and n columns forms a vector space
Linear maps and vector spaces The set of linear maps from V to W forms a vector space
Suppose T is a linear map from V to W, v1,...vn, w1,...wm are bases for V, W. The matrix T w.r.t those bases is the m-by-n matrix M (T) whose entries Ajk are defined by T(vk) = A1k w1 + ... + Amk wm. This also equals the summation from j=1 to m of Ajk wj
M(T) notationally M (T) = M ( T, v1,...vn, w1,...wn )
Matrix addition Adds individual entries
Scalar multiplication for matrices Multiples each entry by some λ
Matrix addition properties for representations of linear maps. Suppose T and S are linear maps from V to W with fixed bases for V and W. M (T+S) = M (T) + M (S)
Scalar multiplication properties for matrix representations of linear maps. Suppose T is a linear map from V to W with fixed bases for V and W. M (λT) = λM (T)
Matrix multiplication properties for representations of linear maps. Suppose T is a linear map from U to V and S is a linear map from V to W. M (ST) = M(S) M(T)
Matrix multiplication as a summation from m-by-n matrix A and n-by-p matrix B (AB)jk = r=1,...,n ∑ (Ajr)(Brk)
Invertibile, inverse A linear map T from V to W is invertible if there exists a linear map S from W to V such that ST = Iv and TS = Iw. S is called an inverse of T.
If a linear map is invertible, Then its inverse is unique. We denote this inverse T^-1.
A linear map is invertible iff A linear map is bijective (injective and surjective) iff
Suppose V, W are finite-dimensional vector spaces and dim(V) = dim(W) with a linear map T from V to W. Then the following are equivalent: T is invertible, T is injective, T is surjective
Isomorphisms, isomorphic An isomorphism is an invertible linear map. Two vector spaces are called isomorphic if there is an invertible linear map from one vector space onto the other one.
Two finite-dimensional vector spaces over a field F are isomorphic iff Those two finite-dimensional vector spaces have the same dimension iff. (This implies that any finite-dimensional vector spaces V with dim(V) = n are isomorphic to F^n.)
Suppose v1,...vn is a basis of V and w1,...wm is a basis of W and consider the function from linear maps to matrix representations M. M is an isomorphism between L(V,W) and F^m,n
Suppose V and W are finite-dimensional vector spaces and consider L(V,W). Then L(V,W) is finite-dimensional and dim(L(V,W) = dim(V) dim(W)
Invertibility of matrices A square matrix A in Mn(F) is called invertible if there exists another matrix B in Mn(F) such that AB = In = BA
Formula for the inverse of a 2-by-2 matrix | a b | ---> 1 / (ad-bc) | d -c | | c d | |-b a |
Computing the inverse of a matrix We compute the inverse of a matrix by augmenting it with the identity matrix and row reducing it
Let T: V --> W and dim(V) = dim(W). Then T is invertible iff Let T: V --> W and dim(V) = dim(W). Then M(T, v1,...vn, w1,...,wn) is invertible iff
Inverses of bases of the same vector space. Let (a1,...,an) and (b1,...,bn) are bases of V (dim(V) = n). Then M(Iv, (a1,...,an), (b1,...,bn)) is invertible with the inverse given by M(Iv, (b1,...,bn), (a1,...,an))
Change of basis formula. Suppose T is a linear map from V to V and let (u1,...,un) and (v1,...,vn) be bases of V. Let A = M(T, (u1,...,un), (u1,...,un)), B = M(T, (v1,...,vn), (v1,...,vn), and C = M(T, (u1,...,un), (v1,...,vn)). A = (C^-1) B C
Invariant subspace Let T be in L(V) and U be a subspace of V. We say U is invariant under T if for all ui in U, T(ui) is in U.
Eigenvalues and eigenvectors Suppose T is in L(V). λ in F is called an eigenvalue of T if there exists a non-zero u in V such that Tu = λu. If this is true, u is called an eigenvector of T corresponding to λ.
V has a one-dimensional invariant under T iff T has an eigenvalue iff
Equivalent conditions to be an eigenvalue. Suppose V is finite-dimensional, T is in L(V), and λ is in F. Then the following are equivalent: a) λ is an eigenvalue of T b) T - λI is not injective c) T - λI is not surjective d) T - λI is not invertible
Suppose λ1,...,λm are distinct eigenvalues of T and v1,...,vm are corresponding eigenvectors. Then v1,...,vm are linearly independent.
V, W are finite-dimensional vector spaces and T is a linear map from V to W. If dim(V) < dim(W), Then T is not surjective
Created by: mejones
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