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Gen Chem (9)

QuestionAnswer
Isobaric An isobaric process is a type of thermodynamic process in which pressure remains constant.
Isochoric An isochoric process is a type of thermodynamic process that occurs at constant volume.
Adiabatic An adiabatic process is a type of thermodynamic process in which there is no heat exchange between the system and its surroundings.
Isothermal An isothermal process is a type of thermodynamic process in which temperature remains constant.
Endothermic An endothermic process is a type of thermodynamic process in which the system absorbs heat from their surroundings, causing a decrease in temperature.
What is the difference between kinetics and thermodynamics? Thermodynamics describes whether a reaction is spontaneous; kinetics describes how fast a reaction occurs, independent of spontaneity.
What is the general rate expression for the reaction aA + bB → cC + dD? Rate = −(1/a)Δ[A]/Δt = −(1/b)Δ[B]/Δt = (1/c)Δ[C]/Δt = (1/d)Δ[D]/Δt
Why are negative signs used for reactants in rate expressions? Reactant concentrations decrease over time, making Δ[A]/Δt negative. The negative sign corrects this to give a positive rate.
What is the general form of a rate law? Rate = k[A]ᵐ[B]ⁿ, where k is the rate constant, m and n are reaction orders determined experimentally, and only reactants are included.
What is the overall reaction order? The sum of all individual reactant orders (m + n).
What are the three factors that affect the rate constant (k) and reaction rate? Temperature (↑T → ↑k and ↑rate), activation energy (↓Eₐ → ↑k and ↑rate), and reactant concentration (↑[reactants] → no effect on k, but ↑rate — except in zero-order reactions).
What is the rate law, concentration vs. time graph, and k units for a zero-order reaction? Rate = k [A] vs. time is linear with slope −k k units are M·s⁻¹.
What is the rate law, concentration vs. time graph, and k units for a first-order reaction? Rate = k[A] ln[A] vs. time is linear with slope −k k units are s⁻¹.
What is the rate law, concentration vs. time graph, and k units for a second-order reaction? Rate = k[A]² 1/[A] vs. time is linear with slope +k k units are M⁻¹·s⁻¹.
How do you determine reaction order from experimental data? Hold one reactant constant between two trials, divide the rate ratio by the concentration ratio raised to a power x, and solve: (concentration ratio)ˣ = rate ratio.
What are the three integrated rate laws? Zero-order: [A]t = −kt + [A]₀ First-order: ln[A]t = −kt + ln[A]₀ Second-order: 1/[A]t = kt + 1/[A]₀
What is the rate determining step (RDS)? The slowest elementary step in a reaction mechanism; it determines the overall rate law. The RDS has the highest activation energy.
How do you write the rate law from a reaction mechanism? Use only the reactants and their coefficients from the RDS. The coefficients become the reaction orders (exponents).
What is a reaction intermediate? A species produced in one elementary step and consumed in a later step; it does not appear in the overall reaction equation.
What is a catalyst and how does it differ from an intermediate? A catalyst lowers Eₐ by providing an alternative pathway and is regenerated at the end of the reaction. An intermediate is produced mid-reaction and consumed before the reaction is complete.
How do you identify a catalyst vs. intermediate in a reaction mechanism? A catalyst appears as a reactant first, then reappears as a product. An intermediate appears as a product first, then is consumed as a reactant.
What are the three conditions of collision theory for a reaction to occur? Molecules must collide; they must collide with the proper orientation; they must have sufficient energy to overcome the activation energy barrier.
Is activation energy (Eₐ) affected by temperature? No. Eₐ is independent of temperature. Only a catalyst can change Eₐ. Temperature helps reactants overcome Eₐ but does not change its value.
What is a half-life? The time required for half the reactant to be converted to products.
What are the three half-life equations and how does each relate to concentration? Zero-order: t½ = [A]₀/2k (half-life decreases as concentration decreases) First-order: t½ = 0.693/k (half-life is independent of concentration) Second-order: t½ = 1/k[A]₀ (half-life increases as concentration decreases)
Why are radioactive decay reactions significant in kinetics? They follow first-order kinetics, meaning their half-life is constant and independent of the amount of reactant remaining.
Created by: smurtab
 

 



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