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orgo 4/30

QuestionAnswer
OsO4 adds two OH groups to the same side of the alkene to give a cis-1,2-diol
B2H6 / diglyme, then H2O2 / NaOH converts an alkene into an anti-Markovnikov alcohol; the OH ends up on the less substituted carbon
CH3CO3H, then NaOH / H2O first forms an epoxide, then opens it to give a trans-1,2-diol
CH3CH2MgBr, then H2O adds a two-carbon ethyl group to ethylene oxide and gives a primary alcohol with a longer chain
CH3OH, CH3ONa promotes SN2 ether formation; one side becomes the nucleophile and replaces a leaving group to form an ether
CH3OH, H2SO4 acid-catalyzed alcohol addition / ether formation
CH3MgBr, ether; then H3O+ adds a methyl group to a carbonyl carbon, converting the carbonyl into a more substituted alcohol
H2O, HgSO4, H2SO4 hydrates an alkyne to a ketone; the triple bond is converted into a carbonyl
K2Cr2O7, H2SO4, H2O oxidizes a secondary alcohol to a ketone
O3, then H2O ozonolysis cleaves the double bond into carbonyl compounds
LiAlH4, then H2O strong reduction; converts some carbonyl derivatives into alcohols
H2, Lindlar catalyst, then H2SO4, H2O partially reduces an alkyne first, then hydrates it to a ketone
H2O, H+ acid-catalyzed hydrolysis; usually breaks an acetal back to the carbonyl compound
excess CH3OH, catalytic H2SO4 converts an aldehyde into a dimethyl acetal; the carbonyl oxygen is replaced by two OCH3 groups
H2O, acid catalyst, starting from a nitrile hydrolyzes the nitrile into a carboxylic acid; the C#N group becomes CO2H
H2O, H+, starting from an ester hydrolyzes the ester into a carboxylic acid plus alcohol
H2O, H+, starting from an acetal regenerates the aldehyde or ketone
H2O, H+, starting from an alkene in hydration conditions adds H and OH across the double bond to make an alcohol
H2SO4, alcohol, and heat drives Fischer esterification; a carboxylic acid + alcohol becomes an ester + water
H2SO4, H2O, after a cyclic acetal hydrolyzes the acetal back to the original carbonyl and releases the diol/alcohol used to form it
H2O2, NaOH, after hydroboration replaces the alkene with an anti-Markovnikov alcohol and keeps the double bond from becoming a ketone
H2SO4, H2O, after hydration of an alkene gives the Markovnikov alcohol; the OH goes to the more substituted carbon
H2SO4, H2O, after an acetal breaks the protecting group and gives back the aldehyde/ketone
Created by: lily_scav
 

 



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