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STATS test 2
| Question | Answer |
|---|---|
| σ | SD |
| X | score |
| μ | mean |
| How to find z score | X-μ/σ |
| How to find X | X= z x σ + μ |
| 1SD away | 68% |
| 2SD away | 95% |
| 3SD away | 99.7% |
| How to find p̂ | m x 1-p/n squared |
| How to find q | 1-p̂ |
| How to find SE of p̂ | p x q / n squared |
| 95% CI | p +- 2(SE) |
| 68% CI | p +- 1(SE) |
| 99.7% CI | p +- 3(SE) |
| At least 10 “successes” and 10 “failures” | 𝑛𝑝 ≥ 10 and 𝑛𝑞 ≥ 10 |
| standard error | S𝐸(𝑝̂ ) = √𝑝̂ 𝑞̂/𝑛 where 𝑞̂ = 1 − 𝑝 |
| Compute a confidence interva | 𝑝̂ ± 𝑧∗ × √𝑝̂ 𝑞̂/𝑛 |
| For a 90% confidence interval z= | 1.645 |
| For a 95% confidence interval z= | 1.96 |
| For a 99% confidence interval z= | 2.576 |
| A confidence interval for a population mean 𝜇 | 𝑦̅ ± 𝑡∗ × 𝑠/√𝑛 |
| t = | Df = n-1 then .9, .95, .99 |
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