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Chem Test

acids/bases

QuestionAnswer
arrhenius def acid contains H+ ions and bases contain OH- ions -acid is a substance that increases the concentration of hydrogen ions in an aqueous solution (produces H+ when dissolved) (OH- for bases) -ONLY WORKS FOR H2O SOLUTIONS
bronstead def acids donate protons (H+) and bases accept protons acid is a substance that can donate a proton to another substance base is a substance that can accept a proton
the color of phenolphthalein in an acid or base acid - colorless neutral- colorless base - pink
he color of bromthymol blue in an acid or base acid - yellow neutral - green base - blue
acid properties sour taste corrosive to metals (react with metals to forming H2 gas, process damages metal) react with indicators electrolytes react with bases
base properties bitter taste caustic (react with skin, ahir, protein ect.) slippery react with indicators electrolytes react with acids
strong acids list HCL - hydrochloric HBr - hydrobromic HI - hydriodic HNO3 - nitric HClO4 - perchloric, and HClO3, H2SO4 - sulfuric
strong bases list group I and Sr, Ba, Ca hydroxides Ca(OH)2 Sr(OH)2 Ba(OH)2
NH4 + amonium weak acid
NH3 ammonia weak base
formula for pH and pOH pH = -log [H+] pOH- = -log [OH-] M of a base is the [OH-] and M of an acid is the [H+] -when we use {H} or {OH}, we are assuming that the {H} = the initil acid concentration (AKA this only works for strong acids/bases cause they fully dissociate)
how to convert [H+ ] into [OH] and vise versa Kw = [H+] [OH-} Kw = 1 x 10 ^-14 (no for sig figs) [H+] vs [OH-], whichever is bigger determined whether its a base , acid, or neutral substance if there is more than 1 H+ or OH in a compound (Ca(OH-)2) then multiply the [] by the amound of H or OH
relationship between pOH and pH pOH + pH = 14
To convert pH into hydrogen ion concentration [H] = 10^-pH
how to write net neutralizationequations for acid/base rxns -all aq -always a single arrow -leave out spectator ions (SA & SB: ion that is not H or OH is a spectator ion) -for ionic compounds, anything but H or OH is a sp. ion -if you can't make HOH then just stick them together
after the equivalence point of a titration is reached, how do you know if something is acidic or basic strong acid + strong base = neutral weak acid + strong base = weak base strong acid + weak base = weak acid weak acid + weak base = unpredicable (dependent on Ka vs Kb)
what is the formula for a hydronium ion H3O+
is naturally occuring rainwater acidic, basic, or neautral -normal is slightly acidic because of CO2 in the atmosphere dissolving in water to form H2CO2 acid if SULFUR and NITROGEN MONOXIDE form, reactions occur producing harmful levels of acidity
in a titration, what do you do you add base to an acid until it changes colors -the strength of the acid/base does NOT determine a titration, only the moles of acid VS base
amphoteric the substance can act as an acid or a base - it becomes the opposite of what you put it with EX: water -when by itself, it might want to be one thing, but mixing it with an acid or base forces it the other way
alkaline descibes soltuions with a pH greater than 7
how to calculate the pH when the Ka and initial M is provided WRITE THESE STEPS IN YOUR WORK 1. disossiation equa. 2. expression 3. ICE chart and either OH- or H+ is the variable (X) 4. in E row for the reactant "assume X is small" (WRITE THIS) 5. plug into expression & solve 6. find pH or pOH use quadratic equation if u dont assume x is small
new sig fig rule for logarithms add one sig fig when taking the log (applies to natural and negitive logs too) drop one sig fig when taking the inverse log
monoprotic the acid only gives off 1 H+ -assume eveything is this unless given a reason to think otherwise
diprotic the acid gives off 2 H+
triprotic the acid gives off 3 H+
polyprotic acid can give off more than 1 H -diprotic might give off one H in certain situation, it doesn't ALAWYS give off 2 it just has the ability to -each equation has a differ. K (they get smaller each time) -
strong acids def -ionize completely into ions -strong electrolytes (substances that dissociate or ionize into positive and negative ions. These mobile ions carry electric charge through the solution) -usually polar because polarity helps them form ions in water.
when do strong acids or bases NOT ionize completely when there isn't enough H2O in the solution to ionize every molecule
what makes something a strong acid/why do they dissociate completely Hydrogen is bonded to a very electronegative atom That atom pulls electron density away from H The H–X bond becomes very polarized (the bond is easier to break) their conjugate bases are stable.
weak acids (description) the HX is is alawys greater in conc. than H+ -the original [] of H bonded is alawys greater than the [] of H+ given off
types of weak acids (1) molecular weak acids (including organic acids and indicatiors (often written has HIn) -NH4+ -covalently bonded mcs that give off an H+
types of weak acids (2) anions containing ionizable H atoms H3PO4 <--> H+ + H2PO4-1
types of weak acids (3) cations (except Group 1, Ca+2, Cr +2, Ba+2) become hydrated. +1 ions get 2 H20 , +2 ions get 4, +3 ion get 6 1. show the dissociation eq of the compound 2. cation reacting with water to form a complex ion 3. complex ion giving off one OH
types of weak bases (1) 1. Mg, Al, and transition hydroxides 2. molecular (produces OH in water, includes NH3) (include amines --> type of organic mcs) 3. Anions (just an anion with nothing attached to it) (anions derived from WA is itself a WB)
lewis definition acids accept electron pairs, bases donate them (you have to draw the lewis structures for this method)
why will CuCl2 corrode the metal balance tops -the Cu+2 will absorb the H2O from the air and form the complex ion Cu(H2O)6. That will react with the metal top
Ka the ionization constant or acid dissociation constant -if the rxn starts w/ a weak acid use Ka, vice vera for weak base
why don't strongs have Ka or Kb strongs always go forward (they dissociate completely) -if they had one, it would be huge, since the Ka is based on how easily it dissociates (bigger Ka = more dissociation)
why does the Ka get smaller as an acid loses H After losing H⁺: the species becomes more negatively charged Pulling another positive H⁺ off a negative ion is harder
the larger the Ka value... the stronger the WA -the rxn goes forward (with a small Ka the rxn reverses)
relationship of Ka and Kb (of conjugates) Ka (Kb) = 1 x 10^-14 -the constant only applies to a system @ 25 degrees C -the value changes with T -conjugates differ only by 1 proton (H+)
how to find the K overall of a polyprotic acid 1. write the equ for each H 2. write the K expressions for each 3. multiply and cross cancle the K expressions 4. this should equal the overall K equation 5. write a K expression for the overall equ
K overall (polyprotic acids have multiple equations) equals Ka1 (Ka2) (Ka3)
most common buffer Ch3COOH and CH3COO -1
5% rule -used only for weak acid or weak base dissociation -if less than 5% of acid/base conc. dissociate, then the intial conc. of acids/Base is about the same at equilibrium -assume x is small if [H+]/initial conc. x 100 < 5%
why should there always be a strong in a net neutralization equation -the strong pushed the rxn forward -a weak + weak could move backwards
if you do not assume x is small, you can either use the quadratic formula or successive approximation replace the bottom x in expression (the one we assumed was small) with the final [] calculated by assuming x is small -replace the new x value you found into the original equation, and repeat this cycle until you get the same x -value multiple times
if, when asked to write a net ionic equation, they say that the M and V are equal, then the moles of acid = moles of base you can safely assume 1 mol of each to keep it simple
salts defintion something ionic -a cation + anion -can be acidic, basic, or neutral
how to determine if a salt is acidic, neutral, or basic classify each ion separately, then add the results if there is a WA and WB combo, then compare the Ka to the Kb Ka > Kb = acidic kb > Ka = basic -a SA + SB = neutral (neutral ions don't have neutralization equations)
NBA chart: neutral anions (anything neutral is a spectator ion) Cl-, Br-, I-, NO3-, ClO4- -all the anions from the strong acids (except SO4)
NBA chart: neutral cations Li+, Na, K, Rb, Cs, Ca, Ba, Sr (group 1 + SrBaCa) -excpet francium cause they only appear during radioactive decay and don't last long
NBA chart: basic anions HCO3- HS F- CO3-2 S-2 PO4-3 CN- NO2- HPO4 SO4-2 CH3COO
NBA chart: basic cations none -positive ions can't consume a positive ion (bases accept H+) -they can't produce OH- on their own -NOTE: amines are usually basic
NBA chart: acidic anions HSO4 H2PO4
NBA chart: acidic cations Mg+2 Al+3 NH4+ transitions
when asked to write an equation if a salt if acidic or basic, write equa showing that it is basic/acidic 1. write dissociation equ, then a separate eq to show the basic/acidic ion reacting to either accept or give off H+ (add water if needed) -might have to form complex ion then show that giving off H (3 equ)
good systems to memorize (acting as acids or bases) NH4+/ NH3 HF/F- H3PO4/H2PO4-/HPO4-/PO4-3 CH3COOh/CH3Coo-
when finding the pH of solution mixtures, and you are mixing a SA and WA, then the pH is due only to the SA -treat the WA like water (it is so weak compared to the strong acid you are just diluting it) -use only the strong H+ moles and divide by the total volume
normality -accounts for the [] of polyprotic acids and bases -equivalence/liter -M x Equ = N
equivalence # of H+ or OH- given off per mole of substance -
for polyprotic acids., although each Ka is different, the volume of base needed to reach the equivalence point is the same for each
eqivalence point the point in a titration where 1 H+ had been completely removed from the acid (there can me multiple points) -when one H+ has been neutralized with one OH-
endpoint the point in a titration where every H+ has been removed from the acid -where all H+ have been neutralized with OH- -It does NOT always mean the moles of acid = moles of base, unless the reaction is 1:1.
how to find the normality or volume of an acid/base Na (Va) = Nb (Vb)
titration curves -endpoint is 1/2 way up the vertical jump -buffer is 1/2 way through the titration (titration starts w/ the first drop of base & ends @ endpoint)
what happens at the half way point of a titration the pH of the solution = pKa of the weak acid being titrated
titration curve for diprotic acids the distance (ml of base) to the 1st equivalence point is equal to the distance to the second equivalence point (AKA endpoint)
protonated state the form of a molecule (or ion) after it has gained a proton (H⁺) In other words, the molecule has accepted a proton, which usually gives it a positive charge or makes it more acidic
deprotonated state the state of a molecule after it has lost a proton (H⁺). So instead of gaining H⁺, it donates one—often giving the molecule a negative charge or making it more basic.
relationship between Ka and Kb (not the equation) When Ka, is high, it means the acid is strong and it donates protons easily. Consequently, the conjugate base has a much lower tendency to accept protons, which means its Kb is lower. It’s basically an inverse relationship between Ka and Kb.
if the weak acid and conjugate base versions of an indicator are equal, then the pH that the titration ends at is = the pKa of the indicator -we select indicators based on their pH at the endpoint
what changes in pH are visible to the human eye can only detect about a one-unit shift. So, for example, if the pH goes from 7 to 8, that's noticeable, but a change from, say, 7.1 to 7.2 might not really be perceived visually
-SA & SB titration curve - has largest vertical jump cause once all SA is neutralized, you're adding base to H2O -any indicator with a Ka within this large jump will work, so any indicator anywhere near the endpoint will work
what is present in significant amounts if strong base is added to a buffer (the buffer is basic) yep, a buffer can be either acidic or basic. -SB it's not reacting, you are just diluting the strong base
calculate the Ph before any indicator is added -write the dissociation equation for the acid and use an ice chart to solve for [H]
find the pH after a random amount of base is added -subtract the moles of base from the moles of acid -the difference is the excess acid -the moles of OH is the amount of weak base produced -divide both by the total volume -plug into the K expression for the dissociation of the weak acid
calculate pH at the endpoint at the endpoint of a weak acid and strong base titration, you’ll have more of the conjugate base than acid, so change the Ka into Kb -also flip the net equation for the titration so that the base is first
when adding an acid or base at the endpoint of a titration... we only deal with the extra stuff added -the solution is neutral at the endpoint so its basically water
Do we ruin buffers at the endpoint? At the endpoint of a titration, the buffer capacity is essentially lost because the acid is fully neutralized, leaving mostly the conjugate base.
buffer def a solution that resists changes in pH when small amounts of acid or base are added -it is made by combining a weak acid and conjugate base -where the pH is not changing
first way to make a buffer you can mix both a WA and a CB together
second way to make a buffer 'they are made through a reaction 'you can start with one component (WA or CB) and react some of it to it's conjugate -what you add must be a lower quanity than what you started with (too much will neutralize all of the other)
because a weak acid dissociates in water, why isn't it always a buffer -it does not make a significant amount of CB -it dissociates less than 5% -a buffer requires a significant amount of each component
how to choose chemicals to make a buffer at a desired pH if the concentration of the weak acid = the concentration of conjugate base: pH of the solution = pKa of the weak acid -once you have chosen your acids and bases, start with an equal amount of both and adjust
The pH of a buffer solution is determined by the pKa of the weak acid and the ratio of the concentrations of the conjugate base and the weak acid. T
note: if a base or acid is solid, then it doesn't affect the volume much. Just use the volume of the liquid
adding a strong acid to a buffer -the acid reacts with/consumes the conjugate base -(a base would react with/consume the weak acid
Why does adding a strong acid to a buffer not affect the pH very much? (same for adding a SB) the added hydrogen ions are neutralized by the conjugate base in the buffer. This forms the weak acid, effectively using up the added H⁺ ions while leaving some CB left. The ratio of the conjugate base to the weak acid doesn’t shift dramatically
how is pH affected by pouring two acids together they dilute each other. The pH ends up between the acidities of the 2 separate acids
The total moles of WA (weak acid) and CB (conjugate base) in a buffer is essentially constant (as long as you’re only adding small amounts of acid or base). -only the ratio of CB to WA changes The total moles stay the same because you’re just converting one form into the other, not removing them from the system.
how to tell if it's the half-way neutralization point the moles of strong base added = 1/2 the initial moles of weak acid this means that the moles of CB and WA are equal
how to find the K for the neutralization equation of a strong base and strong acid this equation is the reverse for the formation equation of water (the constant for that is 1 x 10^-14) -therefore, reverse the constant (1/1 x 10^-14 OR 1 x 10^14)
at the equivalence point of a SA and SB titration, the cation and anion from the acid and the base come together to form a neutral compound (the ions that are not H or OH) -also the pH is 7 (a SA and WB combo would have a pH of below 7 at the equivalence point)
when, during a titration, does the pH increase or decrease the most right after the equivalence point
if the neutralization equation of an acid and base is the same as an acid dissociation equation for, lets say, NH4, then to find the K of the neutralization rxn divide 1 by the Ka of NH4
amphiprotic A substance that can both donate and accept a proton (H⁺). Key point: This is a subset of amphoteric substances: all amphiprotic substances are amphoteric, but not all amphoteric substances are amphiprotic.
what is the concentration of a [H] and [OH] in a neutral solution is 1 x 10-7 -water dissociated into H and OH in a 1 to 1 ratio -a neutral aq aolution has an equal M of H and OH
relationship between [H] and pH values as the pH increases by one unit, the [h+] decreases by a power of 10 -the power of the [H] is the opposite of the pH 10^-10 = 10
as the [H+] of the acid increases, explain the affect on the strength of the acid none -the strength of an acid does not depend on its molarity
percent ionization (how much of an acid or base actually ionizes in water)
as the [H+] of the acid increases, explain the affect on the percent ionization of the acid even though we have more hydrogen ions, the fraction of acid mcs that accutally ionize becomes smaller -a smaller % of the acid is acctually dissociating -adding H or subtracting water shifts equilib towards the ions
if an acid is diluted, the Ka stays the same -depends only on temperature, not starting concentrations -they all dilute at the same rate
how to determine how an amphoteric compound will behave in a soltuion compare the Ka to the Kb Ka > Kb = acidic kb > Ka = basic
what happens when you add water to a buffer it does not change the pH because it dilutes both parts of the buffer, so the ratio stays the same
are indicators basic, neutral, or acidic WA -if drop it into a base, it will grab the proton off -if drop it in an acid, it will accept a proton OR stay as is -it stays as is in a neutral solution OR both forms (protanated and deprotanated exsist at once) -most indicators are amphoteric
how to choose an indcator the pKa of the indicator should fall within the vertical jump on the titration curve 'at the middle of an indicator's color change (equal amounts of both forms), pH = pKa
 

 



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