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CHEM FINAL
| Question | Answer |
|---|---|
| Calculate the average atomic mass of oxygen, if its abundance in nature is 99.76% o16, 0.04% o17, and 0.20% o18 | (16)(99.76) + (17)(0.04) + (18)(0.20) ------------------------------------------ 100 |
| Atomic Mass | Below Chemical letter |
| Atomic Number | Above Chemical letter |
| Where to find protons | Same as the Atomic number |
| Where to find Electrons | Same as protons (unless charged) |
| Ionization Energy | Right and Up (Increase) |
| Atomic Radius | Left and Down (Increase) |
| Electronegativity | Right and Up (Increase) |
| Ionic Bond | Transfers, Conducts Electricity, High melting and Boiling points, Hard and brittle, Soild at room temp |
| Covalent Bond | Shares, Does not conduct electricity, Low melting point and low boiling point, Mostly gas and liquid at room temp, Two NON-METALS |
| Non-Polar, Polar, Ionic | 0-0.4 Non-Polar 0.5-.17 Polar 1.8+ Ionic |
| Combustion | C1 H2 03 ----> H20 CO2 |
| Empirical Formula | Simplifying charges |
| Bent | Lone pair |
| Tetrahedral | T shape |
| Trigonal Planar | No lone pairs |
| Trigonal Pyramind | Lone pair |