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ap precalc U4 test
ap precalc U4 quiz 1 and test
| Question | Answer |
|---|---|
| what to say when a table is exponential: | f(x) is exponential because the OUTPUT values are proportional by # over consecutive equal length INPUT value intervals |
| what to say when a table is logarithmic: | f(x) is logarithmic because the INPUT values are proportional by # over consecutive equal length OUTPUT value intervals |
| what to say when a table is neither exponential or logarithmic: | CHOOSE ACCORDING TO PROBLEM: -f(x) is neither because neither the inputs nor the outputs are consecutive equal length OR -f(x) is neither because neither the inputs nor outputs are proportional |
| what to say when u proved that 2 equations are inverses: | Therefore, f(x) and g(x) are inverses. |
| change of base formula: | logX/logb (big on top, small on bottom/base in the basement) |
| exponential vs logs on tables: | exponential: y values/outputs multiply by a proportion logs: x values/inputs multiply by a proportion |
| exponential vs logs on graphs: | exponential: horizontal asymptote --- logs: vertical asymptote | |
| how to write the inverse of f(x): | f-1(x) |
| what to do when you are stuck at solving inverses: | change the form and then finish solving (log or exponential) |
| exponential graph: | -1, b 0, 1 1, b |
| logarithmic graph: | b, -1 1, 0 b, 1 |
| check for extraneous solutions in... | logs! no need for exponentials :) |
| U4D9 frq question (with these estimates, using average rate of change, be less than or greater than...? explain.): | On # < x < #, the average rate of change is above/below the graph of f(x) because f(x) is concave up/concave down. Therefore, the estimate of the average rate of change will be greater than/less than the model f(x). |
| for solving logs in inequalities and equations... | check for extraneous!!! don't assume negative = wrong, but plug into log and if it is negative or 0, it is extraneous |
| h(x) = lnx | loge 1/e, -1 1, 0 e, 1 |
| negative in front of log: | reflect over X-AXIS |
| negative in parenthesis of log: | reflect over Y-AXIS |
| change of base formula: | big/little |
| what to do with "u" problem: | -expand -say: let u = #^x -solve like a quadratic and find zeros -go back to #^x -solve for x -cross out extraneous if needed |
Created by:
acuda25