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Proof Reasons - 3

Unit 3 (Triangle Congruences)

QuestionAnswer
Midpoint A midpoint divides a segment into 2 congruent segments
Segment Bisector A segment bisector intersects a segment at its midpoint
Midpoints If two segments have the same midpoint, they bisect each other
Angle Bisector An angle bisector divides an angle into 2 congruent angles
Vertical Angles Intersecting lines form congruent vertical angles
Perpendicular Lines Perpendicular lines intersect to form right angles
Right Angles Right angles are congruent
Linear Pair If 2 angles form a linear pair, they are supplementary
Congruent Supplements If 2 angles are congruent, their supplements are congruent
Corresponding Angles If 2 parallel lines are cut by a transversal, corresponding angles are congruent.
Alternate Interior Angles If 2 parallel lines are cut by a transversal, alternate interior angles are congruent.
Alternate Exterior Angles If 2 parallel lines are cut by a transversal, alternate exterior angles are congruent.
Altitude An altitude of a triangle is drawn from a vertex, perpendicular to the opposite side.
Median A median of a triangle is drawn from a vertex to the midpoint of the opposite side.
Midsegment of a Triangle (1) A midsegment of a triangle joins the midpoints of two sides of a triangle.
Midsegment of a Triangle (2) The mid-segment of a triangle is parallel to the third side of the triangle.
Isosceles Triangle (1) If a triangle is isosceles, two sides of the triangle are congruent.
Isosceles Triangle (2) If a triangle is isosceles, the base angles are congruent.
Equilateral Triangle (1) If a triangle is equilateral, all three sides of the triangle are congruent.
Equilateral Triangle (2) All equilateral triangles are also equiangular.
Isosceles Triangle (3) If two sides of a triangle are congruent, the triangle is isosceles.
Equilateral Triangle (3) If all three sides of a triangle are congruent, the triangle is equilateral.
Right Triangle If a triangle has one right angle, it is a right triangle.
∠A≅∠A Reflexive Postulate
If ∠A≅∠B and ∠B≅∠C, then ∠A≅∠C Transitive Postulate
If ∠A≅∠B and ∠A≅∠C and ∠B≅∠D, then ∠C≅∠D Substitution Postulate
If EF ≅ BG and FG ≅ FG then EF + FG ≅ BG + FG so EG ≅BF Addition Postulate
If EG ≅ BF and FG ≅ FG then EG - FG ≅ BF - FG so EF≅BG Subtraction Postulate
Created by: MrsDavey
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