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TAM335 Exam 2

QuestionAnswer
Navier Stokes Equation F=ma per unit volume and involves 3 of the 4 forces
F = pU^2A Force to stop a jet of fluid with velocity and jet area is related to inertial acceleration, the fluid feels the force via pressure
rate change of momentum fluid momentum changes, from upward to downward, requiring net force down onto fluid and causing a reaction force up
Froude Number average velocity/velocity related to gravity --> compares inertia and gravity, important for open channel motion, gravity controls shape
theta angle of inclination
pgsin(theta) gravitational force per unit volume in the flow direction, if inertial effects are neglected, the p only matters in gravitational force pg
q depends on what other parameters (constant)
gradient of v = 0 conservation of mass continuity, describes balance between inertia, pressure gradients, and newton's second law
Laminar Flow Viscous forces dominate, linear because viscosity is constant, uniform velocity profile
Turbulent Flow Inertial effects cause the pressure drop to increase faster with flow rate, nonlinear because energy losee grows faster with velocity (more wasteful)
"mass of fluid in a closed system never changes" conservation of mass
"a difference in pressure accelerated a fluid parcel" conservation of momentum: pressure gradient created acceleration
"viscosity allows momentum to be transferred" if viscosity is ignored it would elimintae drag and make flow appear "too ideal" and boundary layers and separation would be misled
High or low pressure drop Turbulent flow higher pressure drop
faster jet lower static pressure
large reynolds number inertia dominated, flow would be chaotic
ratio of inertial to viscous determines laminar or turbulent floww
rate of change of momentum fluid equals the net external force
Vavg = Q/A velocity avergae
Q equation ((pi)(d^4)/(128*viscosity*L))(change in p)
reynolds number equation p*V*d / viscosity
mass flow rate m = p (change in V)
force on plate F = (m)(Vin-Vout)
if force on a plate changed and was deflected F = (m)(V)(1-cos(45))
(dp/dt) + p(gradient v) = 0 mass conservation
gradient * pv = 0 continuity for incompressible flow
if reynolds number is greater than 4000 the flow must be turbulent
head loss hf = fLv^2 / d2g
pressure drop p = pg(hf)
Created by: user-1739166
 

 



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