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Diff EQ. Test#2
2.6-5.5
| Question | Answer |
|---|---|
| 2.6) If a DE is Not exact, we find __________________? | intergrationg factor |
| 2.6)If y is independent then the formula | p(x)=My-Nx/N |
| 2.6) If y is independent the the intergrating factor | u(x)=e^∫p(x)dx |
| 2.6) if x is independent then the formulal | q(y)=Nx-My/M |
| 2..6) if x is independent then the intergrating factor | u(y)=e^∫q(y)D\dy |
| 5.1) Standered form of a second order linear | y"+p(x)y'+q(x)y=g(x) |
| 5.1)A second order linear ODE is said to be homogeneous if | g(x)=0 |
| 5.1) The Wronskian W(x) of {x,y} | W(x)=|x y | |x' y'| |
| 5.2) Step One of solving a homogeneous DEs with constant coefficients | switch it into the corsopding characteristic equation: ar^2+br+c=0 |
| 5.2) Step Two of solving a homogeneous DEs with constant coefficients | FInd the determinant, using the formula D=b^2 - 4ac |
| 5.2)Step Two of solving a homogeneous DEs with constant coefficients: If D>0 then "r" =? | r=r1,r2. |
| 5.2)Step Two of solving a homogeneous DEs with constant coefficients: If D>0 then what are the root/s? | two distinct real roots |
| 5.2)Step Two of solving a homogeneous DEs with constant coefficients: If D>0 then the solution will be | y=C1 e^(r1x) + C2 e^(r2x) |
| 5.2)Step Two of solving a homogeneous DEs with constant coefficients: If D=0 then "r"= ? | r=r1 |
| 5.2)Step Two of solving a homogeneous DEs with constant coefficients: If D=0 then what are the root/s? | There is a repeated real root of r1 |
| 5.2)Step Two of solving a homogeneous DEs with constant coefficients: If D=0 then what will the solution be? | y=e^(r1x) (C1+C2)(x) |
| 5.2)Step Two of solving a homogeneous DEs with constant coefficients: If D<0 then "r"= ? | r=ƛ±iw |
| 5.2)Step Two of solving a homogeneous DEs with constant coefficients: If D<0 then the root/s are? | There are two distinct roots complex roots. |
| 5.2)Step Two of solving a homogeneous DEs with constant coefficients: If D<0 then the solution will be? | y= e^(ƛx) (C1 cos(wx) +C2 sin(wx) |
| 5.2)Step Three of solving a homogeneous DEs with constant coefficients: What is the third step? | Determine the arbittrary values C1, C2 by solving IVP's. |
| 5.3) Nonhomogeneous second order linear DE form? | y" + p(x)y' +q(x)y =g (x) |
| 5.3) Nonhomogeneous second order linear DE general solution? | Y=C1 Y1(x) +C2 Y2(x) + Y(x) |
| 5.3)Step One of solving Nonhomogeneous second order linear DE ? | Find the generall solution called the complementary solution of the corresponding homogeneous equation |
| 5.3)Step Two of solving Nonhomogeneous second order linear DE (a)? | Find a particular solution y(x) of the nonhomogeneous Eq. you find this by making an intial guess about the form of the particulatr solution Y(t). |
| 5.3)Step Two of solving Nonhomogeneous second order linear DE (b)? | You Set up the inital guess with the chart in slides. the we sub Y(x) into the nonhomomgenous Eq. and determine the constants |
| 5.3)Step Three of solving Nonhomogeneous second order linear DE ? | The solution is y(x) = yc(x) + Y(x) where yc comes from step1 and Y from step two |