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Carbonyl chemistry

Uni of Notts, fundamentals of inorganic & organic chemistry, first year

TermDefinition
How nucleophilic addition changes carbonyl orbitals Forces double bond domain to break & redistribute pi electrons into the 3 existing sp2 orbitals to hybridise to 4 sp3 orbitals
Main factor affecting carbonyl reactivity Groups adjacent to the carbonyl. This depends on electronegativity, size, attached groups, & lone pairs
Role of the oxygen in carbonyls Very electronegative double-bonded species forming a permanent dipole allowing for nucleophilic attack. The double bond can also be broken to form a resonance hybrid
How nucleophiles add themselves to carbonyl groups (Burgi-Dunitz trajectory) Nucleophiles attack the π* LUMO at a 107* angle to maximise attraction to the LUMO while minimising repulsion from adjacent groups. The nucleophile places its HOMO in the LUMO to form a covalent bond
Grignard reagents Akyl groups covalently bound to MgBr, formed by heating alkyl halides in dry ether with Mg. They make powerful nucleophiles to form alcohols with carbonyls
How Grignard reagents work C-Mg bond is so MgBr+ dissociates & the C- attacks the LUMO to form a tetrahedral alkoxide. The MgBr+ forms a salt with the negatively charged oxygen until it's washed with protons during work-up
How borohydrides work Since hydrogen is more electronegative than boron, it pulls electron density to it making it δ- & allowing the bond to break, forming nucleophilic hydride ions
Cyanide as a nucleophile Once it attacks the LUMO, it forms a reversible tetrahedral intermediate, this becomes irreversible once protonated. This can be reversed though by deprotonating the alcohol & heating causing it to collapse into a carbonyl & expel the CN-
Reactivity of carbonyls - electron explaination The closer in energy the HOMO & LUMO are, there more reactive due to lack of steric hindrance & increased attraction. Negative inductive elements (Cl) lower HOMO energy while vice versa (N) raises the energy gap
Selective reactivity of carbonyls with hydrides Weaker hydrides (Like NaBH4) can only reduce the most reactive carbonyls whereas stronger hydrides (Like LiAlH4) can reduce any carbonyl, even amides
How reduction of cyclic esters (lactones) differs from cyclic amides (lactams) Lactones have each oxygen reduced to alcohols which cleaves the C-O in the ring & forms a linear diol. Lactams have their oxygen removed as AlHO making them cyclic amines due to nitrogen being a better electron donor than oxygen
Reduction of esters part 1 H- adds to carbonyl making an sp3 tetrahedral structure. Lithium forms covalent character bond with O- & is then replaced by aluminium hydride to form a salt called an alumane
Reduction of esters part 2 puts pressure on Al-H causing it to break into an H- which adds to the carbonyl to cleave the C-O bond making an alkoxide leaving group leaving behind an aldehyde
Reduction of esters part 3 A 2nd LiAlBH4 binds to the O- in the same way as the first step to reduce the ketone to an alkoxide which is protonated in workup. This is more efficient since ketones are more reactive than esters
Reduction of amides part 1 H- adds to carbonyl forming tetrahedral, Li binds to the the oxygen before being replace with AlH3 to form an alumane. Since Al oxide is a better leaving group than the amine (higher pKa), the AlHO is removed like an elimination
Reduction of amides part 2 N forms a double bond with an adjacent C, making it a carbocation that it neutralises with its lone pair, to form an iminium intermediate which is highly electrophilic
Reduction of amides part 3 The iminium can be reduced to an amine by the remaining hydride, this is why the C-N bond isn't cleaved in a lactam
How ethanol forms hemiacetal with acetone by nucleophilic substitution With no acid catalyst it forms a tetrahedral intermediate with deprotonated O on the carbonyl & protonated O on the ethanol. The proton moves from oxonium to alkoxide by tautomerisation
Mutarotation Changing the optical rotation in cyclical acetals (such a sugars) by opening the ring with tautomerisation (acid catalysed) to reform the carbonyl, rotating the groups, then recyclizing. This is why glucose forms a racemate
Hemiacetals & acetals Hemiacetal: Central C is bound to -OH & -OR simultaneously Acetal = Central C is bound to 2-OR groups from protonation of the hemiacetal -OH to -OH2+ to be substituted for another alcohol
Why acetal formation always uses E1 & never E2 The σ* LUMO has too many groups around it repelling the nucleophile sterically which is why oxonium is used to produce a water leaving group & an acid catalyst is required
Industrial acetal formation problems The reaction is in equilibrium since it produces water & can be hydrolysed back to hemiacetal making it difficult to keep the process anhydrous
Azeotrope A mixture of 2 liquids which have the same concentration in the gas phase as the liquid phase due to lowering each other's boiling point to the same level
Dean-Stark method of acetal production Toluene azeotropes water & they both boil at 84*C to prevent reaction reversal. A clay molecular sieve &/or excess alcohol can be used on a smaller scale though. A ration of 2:1 alcohol:carbonyl is used with acid catalysis
Geminal carbon A carbon bonded to 2 of the same functional groups e.g., acetal but not hemiacetal
Iminium synthesis part 1 2* amine nucleophilic lone pair attacks carbonyl on aldehyde which protonates the oxygen to alcohol & amine is protonated. Tautomerisation transfers proton from nitrogen to hydroxyl to form an R-OH2+ ion which leaves as water
Iminium synthesis part 2 Lone pair on N donates to carbocation to form a double bond & positive charge, this is iminium & can resonate between the positive charge on the N & C
Enamine Stabilised iminium where the pi orbitals are between 2Cs to form a very conjugated nucleophilic & can be reversed with water. Synthesised from 2* amine & ketone or E1 of iminium, can cyclise to bicyclic iminium
Created by: Beech47
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