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BC Calc - Unit 10

QuestionAnswer
Recursive Sequence each term in the sequence is three more than the preceding // a₁=1, a₂=a₁+3, a₃=a₂+3, ... // we should say "a₁=1" and "aₙ₊₁=aₙ+3" where n=1,2,3,...
When Writing A Recursive Definition Of A Sequence, Include... an initial condition (ex: a₁=1)
Explicit Sequence each term in a sequence can be represented by the ordered pairs (order of term, actual value of term) // find relationship between terms and set up an equation (ex: if terms have liner relationship, use y=mx+b)
Limit Of A Sequence Is Written As... If... as limₙₜₒ∞ aₙ = L // if the terms of the sequence approach a unique number, L, as n increases
If The Limit "L" Of A Sequence Exists... then the sequence converges to L
If The Limit "L" Of A Sequence Does Not Exist... then the sequence diverges
A Series Is... the sum of the numbers in a sequence
Sequence Of Partial Sums (Sₙ), Has Terms... s₁=a₁, s₂=a₁+a₂, ..., sₙ= a₁+a₂+...+aₙ
If The Sequence Of Partial Sums (Sₙ) Has A Limit "L", The Infinite Series... converges to that limit
When An Infinite Series Converges, We Can Write... {∞, ₖ₌₁} ∑aₖ = limₙₜₒ∞ { ₙ, ₖ₌₁} ∑aₖ = limₙₜₒ∞ Sₙ = L
Geometric Series {∞, ₙ₌₀} ∑ar^n = a+ar+ar^2+...+ar^n+... when a≠0
Geometric Series Converges When... 0<|r|<1 // to the sum "a/1-r"
Geometric Series Diverges When... |r|≥1
nth Term Test Of A Convergent Series if "{∞, ₙ₌₁} ∑ aₙ" may converge, then limₙₜₒ∞ aₙ = 0 (0 doesn't tell us anything)
nth Term Test For Divergence if limₙₜₒ∞ aₙ ≠ 0, then "{∞, ₙ₌₁} ∑ aₙ" diverges
Summary Of The nth Term Test if the limit is anything other than 0, it diverges // 0 means it May converge, but is inconclusive
The Integral Test if the function meets the requirements, then "{∞, ₙ₌₁} ∑ aₙ" and "{∞, ₁} ∫ f(x)dx" either both converge or diverge
Requirements For The Integral Test positive, continuous, ultimately decreasing, x ≥ a positive integer greater than or equal to 1, aₙ=f(x)
The Integral Test Resulting In 0 Is Considered... inconclusive
Steps Of The Integral Test check for requirements, solve for the integral, if the limit exists both functions converge & if it does not then both functions diverge
p-Series {∞, ₙ₌₁} ∑ 1/(n^p) // when p is a positive number
p-Series Converges When... p>1
p-Series Diverges When... 0<p≤1
Harmonic Series {∞, ₙ₌₁} ∑ 1/n = (1/1) + (1/2) + (1/2) + ... + 1/n + ...
Harmonic Series Always... diverges (p=1)
Direct Comparison Test let 0<aₙ≤bₙ // compare aₙ to a function that can solve for convergence and divergence
"{∞, ₙ₌₁} ∑aₙ" Converges When... {∞, ₙ₌₁} ∑bₙ converges (remember: bₙ ≥ aₙ)
"{∞, ₙ₌₁} ∑bₙ" Diverges When... "{∞, ₙ₌₁} ∑aₙ" diverges (remember: bₙ ≥ aₙ)
Limit Comparison Test aₙ>0, bₙ>0, and limₙₜₒ∞(aₙ/bₙ) = L // series ∑aₙ and ∑bₙ both converge or diverge
Created by: abievans
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