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CHEM II

Exam 2 - Integrated Rate Laws / Differential Rate Laws

Order & Law EquationEquation
Zero Order Integrated [A] _t = -kt + [A]₀ (slope = -k ; x=time , y=[A])
First Order Integrated ln( [A]_t / [A]₀) = -kt (slope = -k ; x=time , y=ln[A])
Second Order Integrated 1 / [A]_t = kt + 1/[A]₀ (slope = k ; x=time , y=1/[A]_t)
Integrated Rate Laws relationship between concentrations of reactants over time
Zero Order Differential Rate = k[A]° = k (rate of reaction is independent of [A])
First Order Differential Rate = k[A] ¹ (rate is proportional to [A])
Second Order Differential Rate = k[A]² (rate is directly proportional to the square of [A])
Differential Rate Laws relationship between reactant concentration and reaction rate
Created by: emily.zegarra
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