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pd and emf
9.2 - potential difference and the electromagnetic "force"
| Question | Answer | |
|---|---|---|
| volts equation | volts = energy / charge 1 V = 1 JC^-1 | V = J/C |
| potential difference | the number of volts given to the component from the charged particles | |
| electromagnetic force | the number of volts given to the charged particles from a component | |
| link between pd and emf | sum of pd = emf | |
| work done equation | work done = Potential difference x charge OR work done = e.m.f x charge | W = VQ W = epsilon Q |