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# Math 2 (10/20/2022)

### Study The Problems + Formulas

What's the formula to find the Axis of Symmetry? -b/2a
What's the formula to find the Vertex? y=ax^2+bx+c (plug the Axis of Symmetry into the x's)
How do you find the Y? (Hint: y=ax^2+bx+c) Plug 0 into the x's.
How do you find the X? (Hint: y=ax^2+bx+c) Plug 0 into the y.
How do you set up Standard Form? y=ax^2+bx+c
How do you set up Vertex Form? y=a(x-h)^2+k
How do you set up Intercept Form? y=a(x-p)(x-q)
Given the vertex, (-3,-1), and a point, (-2,0), what would the equation look like when those points are plugged in? Do not solve! (Hint: Use the vertex formula) 0=a(-2+3)^2-1
Given the x-intercepts, 9,-1, and a point, (0,3), what would the equation look like when those points are plugged in? Do not solve! (Hint: Use the intercept formula) 3=a(0-9)(0+1)
Vertex vs. Point Which one is the (k,h) and which is the (x,y)? Vertex: (h,k) Point: (x,y)
X-intercept vs Point Which one is the (p,q) and which is the (x,y)? X-intercept: (p,q) Point: (x,y)
What does f(x)= mean? y=
What does c(s)= mean? y=
If you were trying to find the axis of symmetry of the equation below, how would you type that into a calculator? f(x)=5x^2+3x-4 f(x)=5x^2+3x-4 ((-3)/(2x5)) or (-3)/(2x5)
y=-4x^2+8x-5 Rewrite the function in vertex form and solve. y=ax^2+bx+c y=-4x^2+8x-5 y=-4(x^2-2x___)-5 y=-4(x^2-2x+1)-5 (x-1)(x-1) *Answer* y=-4(x-1)^-1
Created by: GabrielleHarris
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