Busy. Please wait.

show password
Forgot Password?

Don't have an account?  Sign up 

Username is available taken
show password


Make sure to remember your password. If you forget it there is no way for StudyStack to send you a reset link. You would need to create a new account.

By signing up, I agree to StudyStack's Terms of Service and Privacy Policy.

Already a StudyStack user? Log In

Reset Password
Enter the associated with your account, and we'll email you a link to reset your password.

Remove ads
Don't know
remaining cards
To flip the current card, click it or press the Spacebar key.  To move the current card to one of the three colored boxes, click on the box.  You may also press the UP ARROW key to move the card to the "Know" box, the DOWN ARROW key to move the card to the "Don't know" box, or the RIGHT ARROW key to move the card to the Remaining box.  You may also click on the card displayed in any of the three boxes to bring that card back to the center.

Pass complete!

"Know" box contains:
Time elapsed:
restart all cards

Embed Code - If you would like this activity on your web page, copy the script below and paste it into your web page.

  Normal Size     Small Size show me how

Chapter 7 Note

Chapter 7 Trig notes

Law of Sines -Used to solve non-rt triangles -To find sides: a/sinA=b/sinB=c/sinC -To find Angles: sinA/a=sinB/b=sinC/c
LoS: The Ambiguous Case (Don't make an A.S.S of your self) Only Applies to Angle Side Side case -Possible no solution, 2 solutions, or 1 solution. -To determine: Solve triangle ABC, find < prime (<') of smallest angle. -Angle prime= supplement of <. -If <A + <B + <' is = to 180 then triangle has two solutions.
Law of Cosines Formulas Given 1 side: a^2=b^2+c^2-2bc(cosA) *b^2=a^2+c^2-2ac(cosB) *c^2=a^2+b^2-2ab(cosC)
Area of Triangle (SAS & Area=S) S=1/2bc(sinA) S=1/2ac(sinB) S=1/2ab(sinC)
Area of Triangle (AAS or ASA & Area=S) S=a^2sinBsinC/2sinA S=b^2sinAsinC/2sinB S=c^2sinAsinB/2sinC
Area of Triangle (SSS & Area=S) S=√s(s-a)(s-b)(s-c) where s=a+b+c/2
Vector Addition & Subtraction Vector U+V=< ux+uy,vx+vy> Vector U-V=< ux-uy,vx-vy>
Scalar Multiplication If, Vector U=< ux,uy> and C=scalar (any real #) then, C(U)=C< ux,uy> or < C(ux),C(uy)> -Simply Mult. the cords by the scalar
Magnitude of Vector lCU + CVl=√a^2+b^2
Dot Product U•V=ux(uy)+uy(vy)
Cosine Theorem U•V=lUllVlcosθ also, cosθ=U•V/lUllVl
Created by: ed_delao