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Ballistic Pendulum
Experiment 1
| Question | Answer |
|---|---|
| Ballistic | Refers to a projectile which travels with its own momentum in a frictional motion |
| Inelastic collision | Momentum conserved, KE not conserved |
| Elastic Collision | Momentum and KE conserved |
| Energy loss | Heat, sound, deformation in bullet and pendulum bob, air resistance. |
| Pendulum | Total mechanical energy conserved. KE of pendulum (after firing) is fully converted to PE. |
| According o law of conservation of momentum | mv = (m+M)V |
| According to Law of Conservation of Energy | Delta PE = KE Also known as the Work - Energy Theorem (m + M)gh = 1/2 (m + M).V^2 |
| Velocity of system, V | V = sqrt[2(m+M)gh / (m+M)] = sqrt(2gh) |
| Velocity of bullet, v | mv = (m+M)V v = (M+m)V/m v = (M+m / m) sqrt(2gh) |
| Height, h | h = l(1-cosx) where x is the angle between the mean and extreme positions of the pendulum string and l is the length of the pendulum string. |
| h | Maximum height reached by the pendulum |
| v | Velocity of the bullet |
| V | Velocity of pendulum |
| Applications | This is one way to measure the speed of a bullet. We can verify the law of conservation of momentum. |
Created by:
seemashenai03
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