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When surveying land, a surveyor refers to the principal meridian that is
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The N1/2 of the SW 1/4 of a section contains how many acres?
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Modern RE Practice 5

Modern Real Estate Practice 5

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When surveying land, a surveyor refers to the principal meridian that is Within the rectangular survey sys area in which the land being surveyed is located. No matter how many ranges/tiers it takes, the description must refer to the principal meridian & the baseline of the survey sys area where the land being described is in.
The N1/2 of the SW 1/4 of a section contains how many acres? 80. A section contains 640 acres. A 1/2 of 1/4 of 640 equals 80 acres. Using decimals, the equation is 0.5 x 0.25 x 640 = 80.
In describing real estate, the method that may use a property's physical features to determine boundaries and measurements is Metes & bounds. Monuments are the turning pts in the metes (distance) & bounds (direction, not boundary) method describing property. Here natural, tangible features, like a distinct rock or great tree were at times used as monuments.
A buyer purchased a half-acre parcel for $2.15 per square foot. What is the selling price of the parcel? $46,827. An acre consists of 43,560 sq. ft.; therefore, a half-acre is 21,780 sq. ft. If each sq. foot sells for $2.15, 21,780 sq. ft. x $2.15 per sq. ft. = $46,287.
How many acres are contained in the tract described as "beginning at the NW corner of the SW1/4, then S along the west line to the SW corner of the section 2,640 ft, more or less, to the SE corner of the said SW1/4, then in a straight line to the POB?" 80 acres. The area described is a triangle formed when a quarter of a section is cut from one corner to the opposite corner. A section has 640 acres, a quarter-section has 160 acres, and half of that quarter has 80 acres.
If a farm described as "the NW1/4 of the SE1/4 of Section 10, Township 2 North, Range 3 West of the 6th. P.M." sold for $4,500 an acre, what was the total sales price? $180,000. Disregard all elements of the description except those showing area. It is a 1/4 of a 1/4 of a section, or 1/16 of 640, or 40 acres. When sold, each acre brought $4,500, so the gross selling price is calculated as: 40 acres x $4,500 = $180,000.
As a legal description, "the northwest 1/4 of the southwest 1/4 of Section 6, Township 4 North, Range 7 West" is defective because it contains no reference to Principal meridian. A property description based on the rectangular survey sys must always make reference to the principal meridian & the baseline of the survey sys area where the property lies. This description makes no reference to a principal meridian.
A buyer purchases 4.5 acres of land for $78,400. An adjoining owner wants to purchase a strip of this land measuring 150 ft by 100 ft. What should this strip cost the adjoining owner if it is sold for the same price per sq ft originally paid? $6K. Price divided by area (in sq. ft.) gives cost per sq. ft. The area is 4.5 times the size of an acre (4.5 x 43,560 = 196,020) $78,400 divided by 196,020 = $.40 per sq. ft. The sq. ft. of 100 by 150 ft. lot is: 150 x 100 = 1,500. 1,500 x .40 = $6K
Which of the following are NOT basic components of a meters-and bounds description? Base line, principal meridian, and townships. Base lines, meridians, and townships are elements of the rectangular survey system, not the metes-and-bounds system.
A property contains 10 acres. How many lots of not less than 50 ft. by 100 ft. can be subdivided from the property if 26,000 sq. ft. were dedicated for roads? 81. Ten acres is 10 x 43,560 = 435,600 sq. ft. Subtract 26K (for roads) leaves 409K sq. ft. Each lot's area is 50x100 or 5K sq. ft. Divide the available sq. ft. by the sq. ft. needed: 409K/5K = 81.92. Each lot must be less than 50x100 so it is 81.
A parcel of land is 400 ft by 640 ft. The parcel is cut in half diagonally by a stream. How many acres are in each half of the parcel? 2.94. The parcel is 256K sq. ft. (400x640 = 256K) Half of it is 128K. Each acre requires 43,560 sq. ft. So 128K/43,560 = 2.938 acres. Round it to nearest hundredth is 2.94.
What is the shortest distance between Section 1 and Section 36 in the same township? Four miles. The shortest distance from Section 1 to Section 36 is from the bottom of Section 1 to the top of Section 36, or four miles.
In any township, what is the number of section designated as the school section? 16. Section 16 is one of the centrally located section in the standard township and is designed as the school section.
The LEAST specific method for identifying real property is Street address. A legal description is a precise method of identifying a parcel of land & includes metes & bounds, rectangular survey, & lot & block as methods that can be used for ID. A street address isn't a legal description, therefore not as precise.
POB Point of Beginning
The section marked A (the bottom right corner of a diagram) is which of the following? Section 36. Starting with the upper left corner as number 1, sections of a township are numbered right to left, left to right, right to left and so on until reaching the number 36.
Created by: jr84
 

 



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