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Nat BK Ch5 & CT Ch5
| Question | Answer |
|---|---|
| The LEAST specific method for identifying real property is A)lot and block. B)metes and bounds. C)rectangular survey. D)street address. | Street address A legal description is a precise method of identifying a parcel of land & includes metes-and-bounds, rect survey, & lot-and-block as methods. A street address is not a legal description and, therefore, not as precise. |
| In describing real estate, the method that may use a property's physical features to determine boundaries and measurements is A)lot and block. B)rectangular survey. C)metes and bounds. D)government survey. | metes and bounds Monuments = turning pts, natural features, = monuments. Stream = boundary Metes is distance; bounds is direction. Description gives distance in compass direction from point of beginning (POB), then from each monument, until returns to POB |
| As a legal description, "the northwest ¼ of the southwest ¼ of Section 6, Township 4 North, Range 7 West" is defective because it contains no reference to A)a record of survey. B)lot numbers. C)boundary lines. D)a principal meridian. | Principal meridian. A prop description based on the rectangular survey system always has the principal meridian and the base line of the survey system area in which the property lies. This description makes no reference to a principal meridian. |
| In any township, what is the number of the section designated as the school section? A)1 B)36 C)25 D)16 | Section 16 is one of the centrally located sections in the standard township and is designated as the school section. |
| A property contains 10 acres. How many lots of not less than 50 feet by 100 feet can be subdivided from the property if 26,000 square feet were dedicated for roads? A)82 B)83 C)81 D)80 | 1acr=43,560 ft2 10 acrs × 43,560ft2=435,600ft2 435,600-26,000ft2 for roads=409,600ft2 50' ×100'=5,000ft2 409,600 sq ft ÷ 5,000 square feet = 81.92. Each lot must be "not less than 50 feet × 100 feet," the property can be subdivided into 81 lots |
| Which of the following are NOT basic components of a metes-and-bounds description? A) Tangible and intangible monuments B) Points of beginning C) Base lines, principal meridians, and townships D) Degrees, minutes, and seconds | Base lines, principal meridians, and townships. Base lines, meridians, and townships are elements of the rectangular survey system, not the metes-and-bounds system. |
| A buyer purchases 4.5 acres for $78,400. An adjoining owner wants to purchase a strip of this land measuring 150 ft x100 ft. What should this strip cost if it is sold for the same price per sq ft originally paid? A$3,000 B)$6,000 C)$9,400 D)$7,800 | 15,000/X = 196,020/78,400 196,020X = 1,176.000,000 1,176.000,000/196,020 = 6000 |
| A parcel of land is 400 feet by 640 feet. The parcel is cut in half diagonally by a stream. How many acres are in each half of the parcel? A)5.88 B)2.75 C)2.94 D)5.51 | 2.94. The parcel is 256,000 sqft: 400'×640 =256,000 sqft. Half is 128,000 square feet. Each acre requires 43,560 square feet. Therefore: 128,000 sq ft ÷ 43,560 sq ft per acre = 2.938 acres (rounded to three decimal places). The nearest answer is 2.94. |
| A buyer purchased a half acre parcel for $2.15 per sqft. What was the selling price of the parcel? A) $774 B)$1,376 C)$46,827 D)$93,654 | C. 1 acre = 43,560 sq ft. |
| The principal method of delineating property boundaries or legal descriptions in CT is known as the A)colonial block grant system B)system of principal meridians and baselines C)system of metes and bounds D)rectangular survey system | C)system of metes and bounds |
Created by:
jSmolenski7