Question
multiplying the psi by 2.31.
click below
click below
Question
Normal Size Small Size show me how
Math 3
Question | Answer |
---|---|
If the pressure (psi) is known, The height of the water column can be determined by multiplying the psi by 2.31. | psi X 2.31 = Feet of Head |
What is head pressure? | |
A pressure gauge at the bottom of a storage tank reads 30 psi. What is the water level in the tank? | Convert psi to feet of head 30 psi x 2.31 = 69.3 feet of water above the gauge |
If the height of a column of water is known, the pressure it exerts can be determined by dividing the feet of head by 2.31. | Feet of Head/2.31 = psi |
The reservoir level is 115 feet above the pump discharge. What is the discharge pressure on the pump? | Convert feet of head to psi. 115 feet/2.31 = 49.8 psi |
A pump is installed at 5320 feet above sea level. The overflow of the reservoir is at 5460 feet above sea level. What is the discharge pressure on the pump in psi? | A.Find the difference in elevation 5460 feet â 5320 feet = 140 feet of head B.Convert feet of head to psi 140 feet = 60.6 psi (140÷2=60.6) |
A discharge pressure gauge on a pump reads 72 psi when the pump is running. The pressure gauge at the top of a hill 40 feet above the pump reads 45 psi. What is the friction loss in the pipe in feet of head? | A.Find the difference in the pressures 72 psi â 45 psi = 27 psi B.Convert psi to feet of head 27 psi x 2.31 = 62.4 feet of head C. Subtract the difference in elevation to find the friction loss 62.4 feet â 40 feet = 22.4 feet of head |
The amount of water moving through the system can be measured in one of three different units. They are: | GPM; MGD; CFS. |
What are the conversions for measuring water flowing in the system? | mgd x 700 = gpm; cfs x 449 = gpm; gpm = mgd/700; gpm = cfs/449; |
A system uses 2 mgd. How many gallons per minute does it use? | A. Convert mgd to gpm 2 mgd x 700 = 1400 gpm |
A pipeline has a carrying capacity of 3 cfs. How many gpm can it handle? | A. Convert cfs to gpm 3 cfs x 449 = 1347 gpm |
A well pumps 350 gpm. How many mgd will it pump? | A. Convert gpm to mgd 350/700 = 0.5 mgd |
(Volume = L x W x H) A sedimentation basin is 60' long by 40' wide and 10' deep. What is the volume of the tank in cubic feet? | 60 x 40 x 10 = 24000 cubic feet |
What is the volume of a tank that is 22 feet long, 18 feet wide, and 10 feet deep? | |
The volume of a circular tank can be determined by multiplying the area of the by the height (or depth) of the tank. | Volume of circular tank (cu. ft.) = 3.1416 x r x r x H Or Volume of circular tank (cu. ft.) = d x d x 0.785 x H |
A sedimentation basin is 60'in diameter and 12' deep. What is the volume of the tank? | A. Calculate the volume 3.1416 x 30' x 30' x 12' = 33,900 cubic feet or 60' x 60' x 0.785 x 12' = 33,900 cubic feet |
How would you calculate the volume of a tank or pipe in gallons rather than cubic feet | This is determined by multiplying cubic feet by 7.48. Cubic feet x 7.48 = gallons |
A sedimentation basin is 60' long by 40' wide and 10' deep. What is the volume of the tank in cubic feet? | A. Calculate the volume 60' x 40' x10' = 24,000 cu. ft. B. Convert cubic feet to gallons 24,000 cu. ft. x 7.48 = 179,500 gallons |
The number of gallons contained in a one-foot section of pipe can be determined by squaring the diameter (in inches) and then multiplying by 0.0408. To determine the number of gallons in a particular length of pipe multiply the gallons per foot by the nu | |
The number of gallons contained in a one-foot section of pipe can be determined by: | squaring the diameter (in inches) and multiplying by 0.0408. To get the number of gallons in a length of pipe multiply the gallons per foot by the number of feet of pipe. |
Define Detention Time. | |
The theoretical (calculated) time required for a given amount of water or wastewater to pass through a tank at a given rate of flow. The time required to fill a tank at a given flow. |