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# phyx eqns mechanics

Question | Answer |
---|---|

Kinematic for final velocity | vf = at + vi |

Kinematic for final velocity squared | vf ^ 2 = vi ^2 + 2ax |

Kinematic for displacement | x= vi t + 1/2 at^2 |

Displacement with constant acceleration | Δx = ½ (vf + vi) Δt |

Newton's Law of Gravity | F= (G m1 m2)/ r^2 |

Coulomb's Law | F = (k q1 q2)/ r^2 |

Apparent Weight | F = mg +ma |

Static Friction | F= us FN |

Kinetic Friction | F = uk FN |

velocity in rotational motion | v = 2πr / t |

Centripetal Acceleration | ac= v^2/r |

Centripetal Force | Fc= mv^2/ r or Fc = mac |

Work | W = Fx |

Kinetic Energy | KE = 1/2 mv^2 |

Gravitational Potential Energy | PE= mgh |

Elastic Potential Energy | PEe= 1/2 kx^2 |

Impulse | I = Ft |

Momentum | p = mv |

Position of the Center of Mass | x = m1x1 + m2x2 / (m1 + m2) |

Velocity of the Center of Mass | v = m1v1 + m2v2 / (m1 + m2) |

Position of the Center of Gravity | x = W1x1 + W2x2 / (W1 + W2) |

Torque | T= F l |

Angular Momentum | L = I w |

Moment of Inertia | I = mr^2 |

Angular velocity | w = θ /t ( in radians θ = l/r ) l= arc length |

Rotational Kinetic Energy | KEr = 1/2 I w^2 or 1/2 mr^2 w^2 |

Angular Acceleration | α = w/ t |

Hooke's Law | F= -kx |

Rotational Velocity | w = 2πf |

Period of a Pendulum | T = 2π √ (L/g) |

Period of a Spring | T = 2π √ (m/k) |

Power (two) | P = W/t or P = Fv |

Period | T = 2π / w |

Maximum velocity of a of a rotating object | v = Aw or use KE at equilibrium |

Created by:
cstephens125