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# Quadratic Functions

### Quadratic Functions and their Graphs

Question | Answer |
---|---|

Find the vertex and Axis of Symmetry for the quadratic function f(x)=(x-2)^2+5 | Vertex =(2,5) AoS : x=2 |

f(x)=-3(x+3)^2+1 What direction does the parabola open? Is it narrow or wide? | Opens downward and is narrow. |

Find the Vertex, Axis of Symmetry and the y-intercept of: f(x)=-x^2 + 2x - 1 | Vertex: (1 , 0); AoS: x=1; y-int: (-1 , 0) |

What direction should the parabola shift, and how far, in the equation: f(x)=x^2 + 5? | It should shift upward 5 units |

Describe the shift and reflection of: f(x)=-6(x+2)^2 - 1 | Shifts to the Left 2 and down 1. Parabola opens downward and is narrow. |

What is the equation for finding the Vertex? | (-b/2a , f(-b/2a) |

Find the vertex of the following equation using the vertex equation: f(x)=4x^2 + 4x - 3 | (-1/2, , -4) |

Created by:
JKnie