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Quadratic Functions

Quadratic Functions and their Graphs

Find the vertex and Axis of Symmetry for the quadratic function f(x)=(x-2)^2+5 Vertex =(2,5) AoS : x=2
f(x)=-3(x+3)^2+1 What direction does the parabola open? Is it narrow or wide? Opens downward and is narrow.
Find the Vertex, Axis of Symmetry and the y-intercept of: f(x)=-x^2 + 2x - 1 Vertex: (1 , 0); AoS: x=1; y-int: (-1 , 0)
What direction should the parabola shift, and how far, in the equation: f(x)=x^2 + 5? It should shift upward 5 units
Describe the shift and reflection of: f(x)=-6(x+2)^2 - 1 Shifts to the Left 2 and down 1. Parabola opens downward and is narrow.
What is the equation for finding the Vertex? (-b/2a , f(-b/2a)
Find the vertex of the following equation using the vertex equation: f(x)=4x^2 + 4x - 3 (-1/2, , -4)
Created by: JKnie