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chem exam 4

chem 102

QuestionAnswer
Alkanes CnH2n+2 Only single bonds saturated hydrocarbons anes
meth 1 carbon
eth 2 carbon
prop 3 carbon
but 4 c's
pent 5 c's
hex 6 c's
hept 7 c's
oct 8 c's
complete structual formulas shows connectivity of every atom
condensed structual formulas shows c's and the # of h's it is attached to
structual isomers same formula different structures
NH2 AMINO
NO2 NITRO
F FLUORO
CH=CH2 VINYL
Cl CLORO
OH HYDROXY
Br BROMO
I IODO
naming alkanes 1. find longest carbon chain 2. use appropriate root based on # of c's in longest chain 3. ane prefix 4. name branches 5. organize branch names abc method 6. use carbon numbers to designnate location of branches
alkane combustion something + O2= CO2+ H2O balance equation
alkane halogenation replace 1 or more h atoms with halogens remove one H and one halogen to create "HCl" remaining halogen combines w/ organic compound use di,tri, or tetra to designate #of halogens
alkenees contain at least one C=C CnH2 n= # of n's / 2 enes # carbon chain from end closest to = bond designate double bond location with number
geometric isomers cis and trans put cis/trans before last part of name
alkene hydrogenation = breaks and replaced with H's -degraded to alkane
alkene halogenation = breaks and replaced with Halogen =chloro, flouro, bromo attached to last part of name w/ location ex: 2-chloropropane
Alkynes at least one carbon triple bond CnH2n-2
alkyne combustion something + O2= CO2+ H2O balance equation
alkyne decomposition split CH E CH= 2C +H2
alkyne hydrogenation E breaks and replaced with H's -degraded to alkene
alkyne halogenation E breaks and replaced with Halogen =chloro, flouro, bromo attached to last part of name w/ location ex: 2-chloropropene moles indicate removal of bond amount
aromatics contain at least on benzene
naming aromatics - if one sub, put sub name followed by benzene -if more than one of same sub, use numbering system (lowest number possible) use omp (1,2/1,3/1,4) (ortho,meta, para - if different subs , go by lowest number then abc method
polycyclic aromatics more than 1 benzene fused together
naphtalene 2 benzenes
anthracene 3 benzenes
aromatic hydrogenation - only posible at high temps, and pressure - add Hs
aromatic substitution remove a H from a benzene corner and replace with one of the ions leaving ex: bromobenzene +HBr
aromatic alkyl substitution done with catalyst like CH3CH2Cl -remove a H from a benzene corner and replace with one of the alkyl groups - combine removed H with catalyst to create "HCl"
phenyl Benzene as a sub
Created by: Virajasaur