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Moduel 21

The Algebra of Functions; Composite Functions

QuestionAnswer
(f o g)(x) or(g o f)(x) f(gx) or g(fx)
a.(f+g)(x) b.(f-g)(x) c. (f*g)(x) d. (f/g)(x) f(x) = 3x-5 g(x)=24 -x a 2x-19 b 4x-29 c. -3x^2 +77x -120 d. 3x-5/24-x
(f o g)(9) f(x)= 5x +4 and g(x)= 3x (f o g)(9) = 139
when you see (f o g)(3) it means f(gx)(3) f(x)= x-4 and g(x)=3+5 if you have a problem like f(x) = x-4 g(x)= x+5 we start with the g(x) so g(x)= 3+5 = 8 substitute the 8 in the f(x) problem f(x) = 8 -4 = 4
g(x)=-2x and h(x) squarroot x (g o h) (0) 0
f(x)=7x+12 g(x)=x+4 find (f o g)(x) and (g o f)(x) (f o g)(x)= 7x+40 (g o f)(x)= 7x +16
g(x)= x+9. Find f(x) so that h(x)= (f o g)(x). h(x)= squarroot of( x+9) +9 f(x) = squarroot (x) +9
Created by: Anthonygu
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